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1 answer:
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Answer:
X-5Y-4Z+12=0
Step-by-step explanation:
Plan P1 = 3x-y+2z=1. with A=(1,1,2); B=(2,2,1); we must will find V1 from P1,
V1 =(3,-1,2) and AB = (2-1,2-1,1-2) = (1,1,-1) now we find V2 by vector product.
V2 =V1.X,AB =; (aplying sarrus method)
according to general plan formula a(X-Xo)+b(Y-Yo)+c(Z-Zo); V=(a,b,c)
V2=(-1,5,4) ; A=(1,1,2); so -(X-1)+5(Y-1)+4(z-2)=0 → -X+1+5Y-5+4Z-8=0 →
-X+5Y+4Z+1-5-8=0 → -X+5Y+4Z-12=0 (-1) → Plan equation X-5Y-4Z+12=0
The answer is
In step 2, the addition property of equality was applied.
In step 4, the division property of equality was applied.
Proof that the answer is correct.
