Question

Practice solving multis ASSIGNMENT Solve 3[-X + (2 x + 1)] = x-1.

Answer 1

Answer:

We need to solve this equation:

$3[-x + (2 x + 1)] = x-1$

Firstly, we remove the parenthesis, as it's getting summed and it isn't necessary:

$3[-x+2x+1]=x-1$

Now we operate the brackets:

$3(x+1)=x-1$

We calculate tha prenthesis:

$3x + 3 = x - 1$

And finally, we substract x and 3 on both sides. a

$3x + 3 - x - 3 = x - 1 -x - 3$

$2x = -4$

$\bold{x = \frac{-4}{2} = -2}$

Now, we can verify for x = -2:

$3[-(-2)+(2*(-2)+1)]=-3$

$3[2+(-4+1)]=-3$

$3[2+(-3)]=3$

$3[2-3]=-3$

$3[-1]=-3$ TRUE

Answer 2

...............................