Step-by-step explanation: Is your second one in the right format? I don't understand what it is asking. For the first one, however, you need to free the y being multiplied to 8 and so you are going to undo it by dividing 369 by 8.

7 0

3 years ago

Find a vector equation and parametric equations for the line. (Use the parameter t.)The line through the point (4, 2.1, 3.1) and

olga_2 [115]

Answer:

Vector equation:

$(4 + 6t, 2.1 + 4t, 3.1 - 2t)$

Parametric equations:

$x(t) = 4 + 6t$

$y(t) = 2.1 + 4t$

$z(t) = 3.1 - 2t$

Step-by-step explanation:

The line is parallel to the vector 3i + 2j − k.

So the vector of this line is a multiple of this vector, so i will use 6i + 4j - 2k.

The line goes through the point (4, 2.1, 3.1).

So the parametric equations are:

$x(t) = 4 + 6t$

$y(t) = 2.1 + 4t$

$z(t) = 3.1 - 2t$

The vector equation is:

$(4 + 6t, 2.1 + 4t, 3.1 - 2t)$

3 0

3 years ago

I really need help with #2

sashaice [31]

Answer:

do u still need help. I can help

3 0

3 years ago