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3 years ago

If a population is at Hardy-Weinberg equilibrium...

Biology

1 answer:

jarptica [38.1K]3 years ago

3 0

Answer:

B. (i) yes; (ii)-yes

Explanation:

If a population is at Hardy-Weinberg equilibrium, allele frequencies can be calculated from the given values of genotype frequencies and genotype frequencies can be calculated if the allele frequencies are given.

For a population in Hardy-Weinberg equilibrium; p+q=1

Here, p= frequency of recessive allele and q = frequency of dominant allele.

And p2 + 2pq + q2 = 1

p2= Frequency of homozygous dominant genotype

2pq = Frequency of heterozygous dominant genotype

q2 = Frequency of homozygous recessive genotype

For example, if frequency of homozygous recessive genotype (q2) is 0.40, then, the frequency of recessive allele (q) will be = square root of 0.40= 0.63

Likewise, frequency of dominant allele (p) in this population will be = 1-q = 1-0.63 = 0.37

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3 years ago

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