Answer:
B. (i) yes; (ii)-yes
Explanation:
If a population is at Hardy-Weinberg equilibrium, allele frequencies can be calculated from the given values of genotype frequencies and genotype frequencies can be calculated if the allele frequencies are given.
For a population in Hardy-Weinberg equilibrium; p+q=1
Here, p= frequency of recessive allele and q = frequency of dominant allele.
And p2 + 2pq + q2 = 1
p2= Frequency of homozygous dominant genotype
2pq = Frequency of heterozygous dominant genotype
q2 = Frequency of homozygous recessive genotype
For example, if frequency of homozygous recessive genotype (q2) is 0.40, then, the frequency of recessive allele (q) will be = square root of 0.40= 0.63
Likewise, frequency of dominant allele (p) in this population will be = 1-q = 1-0.63 = 0.37
