The circle with center O has two chords AC and EF which are of same length 9.07.
OD and OB are the two perpendiculars drawn from the center O to the two chords AC and EF .It represents the distance of the chords from the centre.
The circle theorem states: congruent chords are equidistant from the center.
OD is congruent to OB.
Option A is the right answer.
Answer:
l:9
p:16.4
Step-by-step explanation:
l x w = A
A÷w=l
37.8÷4.4=9
2l+2w=P
18+8.4=16.4
The nails less than 2 inches long are the ones that are 1/2”, 1”, and 1 1/2”, if I am reading the table correctly.
4 x 1/2” = 2”
2 x 1” = 2”
2 x 1 1/2” = 3”
2 + 2 + 3 = 7 inches
3 and 2/7 rounded is 3 and 3 times 3 is 9 and that's greater than 3 and 2/7.