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kykrilka [37]
3 years ago
8

There are 33 students in the Chess Club. There are five more boys than girls in the club. Write and solve a system of equations

to find the number of boys and girls in the Chess Club.
My question is this, do I have the right equation to figure this problem?

Boys 5(x) =33
Girls = x

x+5(x)=33
6x =33
6/6. 33/6



x=5.5 this is where I'm lost. What do I do next? Or, do I have it all wrong?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0
<span>There are 33 students in the Chess Clubs. There are 5 more boys than girls in the club.
Now, the equation will be like this
girls = x
boys = x + 5
x + 5x = 33
let’s solve for X
=>  x + (x + 5) = 33
=> 2x + 5 = 33
=> 2x = 33 - 5
=> 2x /2 = 28 / 2
=> x = 14
Thus the number are:
girls = 14
boys = 14 + 5 = 19
=> 19 + 14 = 33</span>



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Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0
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So, the definite integral  \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Given that

\int\limits^1_0 {x^{2} } \, dx = 13

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\int\limits^1_0 {(4 - 6x^{2} )} \, dx

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4    - 6\int\limits^1_0 {x^{2} } \, dx

Since

\int\limits^1_0 {x^{2} } \, dx = 13,

Substituting this into the equation the equation, we have

\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Learn more about definite integrals here:

brainly.com/question/17074932

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