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kykrilka [37]
3 years ago
8

There are 33 students in the Chess Club. There are five more boys than girls in the club. Write and solve a system of equations

to find the number of boys and girls in the Chess Club.
My question is this, do I have the right equation to figure this problem?

Boys 5(x) =33
Girls = x

x+5(x)=33
6x =33
6/6. 33/6



x=5.5 this is where I'm lost. What do I do next? Or, do I have it all wrong?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0
<span>There are 33 students in the Chess Clubs. There are 5 more boys than girls in the club.
Now, the equation will be like this
girls = x
boys = x + 5
x + 5x = 33
let’s solve for X
=>  x + (x + 5) = 33
=> 2x + 5 = 33
=> 2x = 33 - 5
=> 2x /2 = 28 / 2
=> x = 14
Thus the number are:
girls = 14
boys = 14 + 5 = 19
=> 19 + 14 = 33</span>



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Answer:

The margin of error (E)  =0.49

Step-by-step explanation:

Given,

 mean \bar{x}=6.88

 standard deviation \sigma=1.90

 sample size n=41

90\% \quad \text{confidence interval}

Critical value =\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]  

                                                =1-0.90

                                        \Rightarrow \alpha=0.1

Critical value =\frac{z_{0.1}}{2}

                      =z_{0.05}

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The margin of error (E)  =\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }

                                       =1.645\times\frac{1.90}{\sqrt{41} }

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Hence, The margin of error (E) =0.49

Complete question is attached in below.

                     

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Your answer is either A or D
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Solving the whole thing
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Let
x---------------> distance from people living to the city center

we Know that
Zone 1 covers people living within three miles of the city center
Zone 1 ------------> [x < 3 miles]

Zone 2 covers those between three and seven miles from the center
Zone 2 ------------> [ 3 <= x < = 7  miles]

Zone 3 covers those over seven miles from the center
Zone 3 ------------> [  x > 7  miles]

<span>calculate the distance between two points to find the value of x
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case A) point (0,0)  point (3,4)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(4-0)² +(3-0)²]------> √[16+9]
x=√25-------------> x=5 miles

the answer Part A)
people living in (3,4)
x=5 miles -------------> covers Zone 2 [ 3 < =x <= 7  miles]


case B) point (0,0)  point (6,5)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(5-0)² +(6-0)²]------> √[25+36]
x=√61-------------> x=7.81 miles

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x=7.81 miles -------------> covers Zone 3 [  x > 7  miles]

case C) point (0,0)  point (1,2)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(2-0)² +(1-0)²]------> √[4+1]
x=√5-------------> x=2.23 miles

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x=√[(y2-y1)² +(x2-x1)²]----------> √[(3-0)² +(0-0)²]------> √[9]
x=√9-------------> x=3 miles

the answer Part D)
people living in (0,3) 
x=3 miles -------------> covers Zone 2 [ 3 < =x <= 7  miles]

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x=√[(y2-y1)² +(x2-x1)²]----------> √[(6-0)² +(1-0)²]------> √[36+1]
x=√37-------------> x=6.08 miles

the answer Part E)
people living in (1,6) 
x=6.08 miles -------------> covers Zone 2 [ 3 < = x <= 7  miles]

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Answer:

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Given that:

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Nathaniel wants to build 50 birds(B) using lego Blocks, we want to determine how many birdhouses(H) he can build with the remaining Lego blocks.

If B=50

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Therefore, Nathaniel can build at most 3 Birdhouses.

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