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anzhelika [568]
4 years ago
11

WILL MARK BRAINLIEST help answer 4-5 please x

Mathematics
1 answer:
Hunter-Best [27]4 years ago
6 0

Answer:

Step-by-step explanation:

4. A) \frac{13}{100}×79.50 = 10.335

tax=10.335

total cost=79.50+10.335=89.835

B) \frac{13}{100}×189.99=24.6987 = tax

189.99+24.6987=214.6887

5) \frac{20}{100}×544.99=108.998

yes Brittany will have enough money

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A box is filled with 11 blue cards, 2 green cards, and 7 brown cards. A card is chosen at random from the box. What is the proba
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11 blue
2 green
7 brown
total is 20 card
7 out of that 20 are brown
so x out of 100% are brown
7/20=x/100 - cross multiply
700=20x
x=700/20
x=70/2
7 0
3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
What are 3 words that describe the volume of rectangular prisms
lyudmila [28]

Answer:

length*width*height?

Step-by-step explanation:

5 0
3 years ago
Which of the tables represent a function??<br>please help me! asap!​
Katyanochek1 [597]
The answer is table C
For anything to be a function, it cannot have two pairs as my teacher taught me!
For example, let’s take the number 4
Let’s say 4 can take a friend to the fair!
4 decided to take 5 (4,5)
4 CANNOT take anyone else but 5
4 is allowed to take as many 5’s as they want but cannot take any other number
Let’s set up a table

X. Y
4. 5
4. 5
4. 5
This is a function

If the table changed:
X. Y.
4. 5
4. 5
4. 6
This will not be a function
I hope this helps!
8 0
2 years ago
Which of the following is a solution of y &gt; |x| - 6?<br><br> (-5, 1)<br> (-1, -5)<br> (5, -1)
levacccp [35]
Absolute value of x minus 6 is less than y
one way is to jsut make all the x's positive, then subtract them from 6 and see if they are less

sorry for confusing, just read below

(-5,1)
1>|-5|-6
1>5-6
1>-1
true

(-1,-5)
-5>|-1|-6
-5>1-6
-5>-5
false

(5,-1)
-1>|5|-6
-1>-1
false



answer is (-5,1)
4 0
3 years ago
Read 2 more answers
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