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Nadya [2.5K]
3 years ago
11

Please HELP PICTURE SHOWN

Mathematics
1 answer:
Umnica [9.8K]3 years ago
6 0

Answer:

x<−3+√1012 or x>−3−√1012

Step-by-step explanation:

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You drink a beverage with 120 mg of caffeine. Each hour, the caffeine in your system decreases by about 12%. How long until you
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10 hours

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Choose an entree (steak, chicken, fish, or tofu), a side (mac &amp; cheese, green beans, french fries, or bread), and a drink (w
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Y=3/2x+5 in standard form
Lyrx [107]

Answer:

  3x -2y = -5

Step-by-step explanation:

Standard form is ...

  ax +by = c

where the leading coefficient (a, or b if a=0) is positive and a, b, c are mutually prime.

Multiplying the equation by 2 gives ...

   2y = 3x +5

We can subtract 2y+5 to get standard form:

  3x -2y = -5

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3 years ago
If a ball is thrown straight up into the air with an initial velocity of 100 ft/s, it height in feet after t second is given by
Sergeu [11.5K]

Answer:

11 0.1 seconds

Step-by-step explanation:

4 0
2 years ago
What is the problem of this solving?!
nika2105 [10]
     This question can be solved primarily by L'Hospital Rule and the Product Rule.

y= \lim_{x \to 0}  \frac{x^2cos(x)-sin^2(x)}{x^4}
 
     I) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[2xcos(x)-x^2sin(x)]-2sin(x)cos(x)}{4x^3}
 
     II) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)]}{12x^2} \\ y= \lim_{x \to 0} \frac{2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x)}{12x^2}
 
     III) Product Rule and L'Hospital Rule:

]y= \alpha + \beta \\ \\ \alpha =\lim_{x \to 0} \frac{-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)]}{24x} \\ \beta = \lim_{x \to 0} \frac{4sin(x)cos(x)+4sin(x)cos(x)}{24x} \\  \\ y = \lim_{x \to 0} \frac{-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x)}{24x}
 
     IV) Product Rule and L'Hospital Rule:

y = \phi + \varphi \\  \\ \phi = \lim_{x \to 0}  \frac{-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)]}{24x}  \\ \varphi = \lim_{x \to 0}  \frac{[2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)]}{24x}
 
     V) Using the Definition of Limit:

y= \frac{-6*1-4*1-2*1+8*1^2}{24}  \\ y= \frac{-4}{24}  \\ \boxed {y= \frac{-1}{6} }
3 0
2 years ago
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