The answer is 143 KA CHOW
Step-by-step explanation:
Given precision is a standard deviation of s=1.8, n=12, target precision is a standard deviation of σ=1.2
The test hypothesis is
H_o:σ <=1.2
Ha:σ > 1.2
The test statistic is
chi square = ![\frac{(n-1)s^2}{\sigma^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28n-1%29s%5E2%7D%7B%5Csigma%5E2%7D)
=![\frac{(12-1)1.8^2}{1.2^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%2812-1%291.8%5E2%7D%7B1.2%5E2%7D)
=24.75
Given a=0.01, the critical value is chi square(with a=0.01, d_f=n-1=11)= 3.05 (check chi square table)
Since 24.75 > 3.05, we reject H_o.
So, we can conclude that her standard deviation is greater than the target.
Answer:
X= 3 and y=-9
Step-by-step explanation:
let
x+y=-6 be the equation..1
and 4x + y = 3 be the equation..2
now solving the two equations simultaneously using substitution method
- make x the subject in equation 1. thus the equation turns to x=-6-y when you make x the subject
- substitute x= -6-y into equation 2. Thus the equation 2 then becomes 4(-6-y)+y=3
- simplifying it.. -24-4y+y=3 furthermore ,-24-3y =3 .
solving for y in the relation (-24-3y)=3 . group like terms hence the equation changes to -24-3=3y
-27=3y. divide through by 3
as -27/3=3y/3 to obtain
-9=y.
therefore the value for y is -9
put the y value in either of the two equations to obtain x value
substituting it into equation 1
where x+y =-6
put the y value at the position of y to obtain x-9=-6
x=-6+9
x=3
therefore the value for x and y are 3 and -9 respectively.
I think the answer is C though i'm not entirely sure please tell me I'm right or I'm wrong
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Step-by-step explanation:
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