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steposvetlana [31]
3 years ago
13

9 cm

Mathematics
1 answer:
Delicious77 [7]3 years ago
3 0

Answer:

if all the sides of a triangle are doubled

Area increases 4 times

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Write the opposite of each integer.<br> -(-8)<br> -(-65)<br> PLS HELP ME TYSM
otez555 [7]

Answer:

it should be -8 and -65 you would use parentheses first then you would have the negative integers in it's place

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Real life Applications of Polynomials?
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Sep 11, 6:11:06 PM
Aloiza [94]

Answer:

5 inches

Step-by-step explanation:

First of all dont make your sentences long and second this doesnt make sence

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Write <br> 17/25 as a decimal.<br> A) 0.068 <br> B) 0.68 <br> C) 1.471 <br> D) 6.8
ikadub [295]
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Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>​
Ksju [112]

Step-by-step explanation:

(\sec A - \csc A)(1 + \cot A + \tan A)

=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)

=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)

=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)

=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)

=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}

=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}

=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}

=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}

=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)

=\sec^2A\csc A -  \csc^2A\sec A

5 0
3 years ago
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