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Mariulka [41]
3 years ago
9

Which equation or function is linear?

Mathematics
1 answer:
zepelin [54]3 years ago
8 0

9514 1404 393

Answer:

  C.  2y = (2x-1)/4

Step-by-step explanation:

An equation is linear when the exponents of the variables are 1 and the sum of the exponents of the variables in any term is 1.

a) 3xy = 4 . . . . sum of exponents is 1+1=2

b) f(x) = 2/3(1 -x^2) . . . . exponent is 2

c) 2y = (2x -1)/4 . . . . all exponents are 1 (linear)

d) y = 3/(x+1)  ⇒  xy +y = 3 . . . . sum of exponents is 1+1 = 2

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Someone please help me ASAP!!
antoniya [11.8K]

Answer:

B' = (-6,6)

Step-by-step explanation:

The coordinates of B are (-2,2)

If the figure is to become 3 times as large, B' would be 3(-2,2) = (-6,6)

6 0
3 years ago
Triangle A B C is shown. Angle C A B is a right angle. Angle A B C is 30 degrees and angle B C A is 60 degrees. The length of A
marishachu [46]

Answer:

i. sin(C) = \frac{\sqrt{3} }{2}

ii. tan(C) = \sqrt{3}

iii. sin(B) = \frac{1}{2}

Step-by-step explanation:

Given a right angled triangle ABC, with a right angle at A.

<ABC = 30^{0}

<BCA = 60^{0}

AC = 9 = 1

CB = 18 = 2

Applying Pythagoras theorem to ΔABC, we have;

AB = \sqrt{BC^{2} - AC^{2} }

    = \sqrt{2^{2} - 1^{2}  }

   = \sqrt{3}

Thus applying the trigonometric ratios, it would be observed that;

i. sin(C) = \frac{\sqrt{3} }{2}

ii. tan(C) = \sqrt{3}

iii. sin(B) = \frac{1}{2}

3 0
3 years ago
Read 2 more answers
Can someone please answer this!!
photoshop1234 [79]

Answer:

40

To find the area you multiply base times height

Step-by-step explanation:

5 0
3 years ago
The end points of one side of a regular pentagon are (-1,4) and (2,3). What is the perimeter of the pentagon?
marissa [1.9K]
To determine the perimeter of the pentagon, you must first calculate a side length of it. Let's name the coordinates A(-1,4) and B(2,3).

To figure out how far the points are from each other, you have to use the distance formula:
D_{AB}  =  \sqrt{( x_{2}-x_{1})^2+{(y_{2}-y_{1})^2}&#10;
x_{1} =1, x_{2} =-2, y_{1} =2, y_{2} =3
D_{AB}= \sqrt{(2--1)^2+{(3-4)^2}
D_{AB}= \sqrt{(2--1)^2+{(3-4)^2} 
D_{AB}= \sqrt{(2+1)^2+{(3-4)^2}
D_{AB}= \sqrt{(3)^2+(-1)^2}
D_{AB}= \sqrt{9+1}
D_{AB}= \sqrt{10}

Now, the formula for the perimeter of a pentagon is 
P = 5×side length
 
So...
Perimeter = 5×\sqrt{10}

The answer is (2)

8 0
3 years ago
Triangle NLM is reflected over the line segment as
Vladimir [108]
NLM-CAB would be the right answer
3 0
3 years ago
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