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Ann [662]
4 years ago
10

46) through: (3, -5), perp. to y=-x-3 find slope intercept form

Mathematics
1 answer:
sweet-ann [11.9K]4 years ago
7 0

Answer:

y = x - 8

Step-by-step explanation:

The equation of the straight line which is perpendicular to the straight line y = -x -3, will be y = x + c' ....... (1), where c' is a constant.

{This is because the product of the slopes of two mutually perpendicular straight line is -1}

Now, (3,-5) point satisfies equation (1).  

Hence, -5 = 3 +c', ⇒c' = -8.

Therefore, the equation of the required straight line in slope-intercept form is y = x - 8 (Answer)

{Note: The slope-intercept form of a straight line is y = mx + c, where m is the slope of the line i.e. tanФ, and c is the length of y-axis intercept.}

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The 1st and the 5th tables represent the same function

Step-by-step explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

  (x2 , y2) is \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

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# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4

∴ \frac{y-5}{x-4}=\frac{4-5}{6-4}

∴ \frac{y-5}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

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# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5

∴ \frac{y-8}{x-2}=\frac{5-8}{8-2}

∴ \frac{y-8}{x-2}=\frac{-3}{6}=====\frac{y-8}{x-2}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 2) ⇒ simplify

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# (x1 , y1) = (2 , 10) and (x2 , y2) = (6 , 14)

∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14

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∴ (y - 10) = (x - 2)

∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

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# (x1 , y1) = (2 , 9) and (x2 , y2) = (8 , 6)

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∴ 2y - 18 = -x + 2 ⇒ add x and 18 for two sides

∴ x + 2y = 20 ⇒ (5)

- Equations (1) and (5) are the same

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