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Novosadov [1.4K]

3 years ago

15

What two represents quantities that are proportional A.30/36 and 40/46. B.40/48 and 100/120. C.4/9 and 14/19. D. 27/81 and 21/72

please help

1 answer:

lubasha [3.4K]3 years ago

4 0

The answer is 4/9 and 14/19

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Fraction to decimal , problem 27 over 75?

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3 years ago

If you invest $4,500 in an account paying 2% compounded continuously, how much money will be in the account at the end of 4 year

saveliy_v [14]

Total = Principal * e^(rate*years)
Total = 4,500 * 2.718281828459^(.02*4)
Total = 4,500 * 2.718281828459^(.08)
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calculator for checking the answer:
http://www.1728.org/compint.htm

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3 years ago

In a football game, Jim's team gained 7 yards on the first play, lost 2 yards on the second play, and lost 10 yards on the third

Ghella [55]

Answer:

team loss after three games is 5.

Step-by-step explanation:

we will use positive sign for gain and negative sign for loss.

Given

Jim's team gained 7 yards on the first play

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lost 2 yards on the second play

loss of yards = -2

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loss of yards = -10

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3 years ago

ira [324]

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3 years ago

Read 2 more answers

In May you used 900 kilowatt-hours of energy for electricity.

Sloan [31]

Answer:

a) "The total electrical energy use was 3,240,000,000 joules."

b) "The average power use is 1210 watts."

c)

<u>Part 1:</u> "To generate the electricity you used, 810 L is needed."

<u>Part 2:</u> "To generate the electricity you used, 214.00 gal is needed."

Step-by-step explanation:

a)

1 kilowatt-hours = $3.6x10^6$ joules

Converting 900 kilowatt-hours to joules, we have:

$900*(3.6*10^6)=3.24*10^9$ joules, or

Total Electrical Energy use = 3,240,000,000 joules

"The total electrical energy use was 3,240,000,000 joules."

b)

The month of May has 31 days and 1 day is 24 hours. So May has:

31*24=744 hours

Now, we divide 900 kW-hr by the number of hours in the month (744 hrs) to get average power use:

$\frac{900}{744}=1.21$ kW. Since 1000 Watts = 1 kW, we multiply this by 1000 to get the answer in Watts:

1.21 * 1000 = 1210 Watts

"The average power use is 1210 watts."

c)

<u>Part 1:</u>

The conversion efficiency of most generating stations is 33%. So we need to multiply the total electrical energy use (in joules) by a factor of 3 to get the amount of joules required. So:

(3.24 * 10^9)*3 = 9.72 * 10^9 joules

We divide this by 12 million joules to get the number of liters:

$\frac{9.72*10^9}{12*10^6}=810$

So, 810 liters is needed

"To generate the electricity you used, 810 L is needed."

<u>Part 2:</u>

We know that 0.2642 gallons is equal to 1 liters. To get the number of gallons needed, we multiply 810 by 0.2642. So:

810 * 0.2642 = 214.00 gallons

"To generate the electricity you used, 214.00 gal is needed."

7 0

4 years ago