All categories

2 years ago

Stretch your thinking.Rewrite this using the word fewer.Carey reads 10 more pages than lucey

Mathematics

1 answer:

snow_lady [41]2 years ago

8 0

Answer:

Lucy reads 10 fewer pages that Carey

Step-by-step explanation:

The first sentence reads as Carey having more, so Lucy has fewer,

Rewriting it using fewer means that Lucy will be the main subject of the sentence, so Lucy reads 10 fewer pages that Carey is the sentence you want

You might be interested in

Make q the subject of the formula 2(q+p) = 1+5q. Give your answer in the form ap-b/c where a,b and c are all positive integers

musickatia [10]

Answer:

$\frac{2p-1}{3}$

Step-by-step explanation:

Since you want to get q only and q appears in both side of the equation. Try to isolate q to one side.

1) Expand 2(q+p)

2q + 2p = 1 + 5q

2) Move all q terms to one side

5q - 2q = 2p - 1

3q = 2p - 1

3) Divide 3 on both side (to isolate q)

q = $\frac{2p-1}{3}$

8 0

3 years ago

Sixty percent of the runners who ran the marathon finished the race. If fifteen runners finished, then how many runners ran in t

ZanzabumX [31]

Let they be x

$\\ \rm\Rrightarrow 60\%\: of\:x=15$

$\\ \rm\Rrightarrow \dfrac{3}{5}x=15$

$\\ \rm\Rrightarrow x=15\times \dfrac{5}{3}$

$\\ \rm\Rrightarrow x=5(5)$

$\\ \rm\Rrightarrow x=25$

4 0

1 year ago

Solve this equation<br> ×(2)-8×+7=0<br> Solve the equation

yKpoI14uk [10]

Answer:

-7/6

Step-by-step explanation:

2x-8x+7=0

combine like terms

6x+7=0

subtract the 7 from both sides

6x=-7

divide 6 from both sides

-7/6 or -1 and 2/3

7 0

2 years ago

Read 2 more answers

Two college roommates have each committed to donating to charity each week for the next year. The roommates’ weekly incomes are

schepotkina [342]

Answer:

C. 5 weeks.

Step-by-step explanation:

In this question we have a random variable that is equal to the sum of two normal-distributed random variables.

If we have two random variables X and Y, both normally distributed, the sum will have this properties:

$S=X+Y\\\\\ \mu_S=\mu_X+\mu_Y=30+60=90\\\\\sigma_S=\sqrt{\sigma_X^2+\sigma_Y^2}=\sqrt{10^2+20^2}=\sqrt{100+400}=\sqrt{500}=22.36$

To calculate the expected weeks that the donation exceeds $120, first we can calculate the probability of S>120:

$z=\frac{S-\mu_S}{\sigma_S} =\frac{120-90}{22.36}=\frac{30}{22.36}=1.34\\\\P(S>120)=P(z>1.34)=0.09012$

The expected weeks can be calculated as the product of the number of weeks in the year (52) and this probability:

$E=\#weeks*P(S>120)=52*0.09012=4.68$

The nearest answer is C. 5 weeks.

6 0

2 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 mill

abruzzese [7]

Answer:

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year

Step-by-step explanation:

Given that oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 million barrels of oil in the well; six years later 1,500,000 barrels remain.

i.e. if V stands for volume of oil, then

$V' =kV\\dv/V= kdt\\ln V = kt+C\\V = Ae^{kt}$

To find A and k

V(0) = A = 3 million

Hence V = $3e^{kt}$

V(6) = 1.5

i.e. $1.5 = 3e^{6k}\\ln 1.5 =ln 3 +6k\\k = -0.11552$

$V(t) = 3e^{-0.11552t}$

a) Using the above value of k , we have

$V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794$ million per year.

4 0

3 years ago