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Illusion [34]
4 years ago
10

What is the equation of this line?

Mathematics
1 answer:
Illusion [34]4 years ago
5 0
Y=-4
This line also is equals Zero, if that makes any sense lol but y= -4 is the correct equation.
You might be interested in
4x^2-16=x^2+32<br> Using reverse PEMDAS
telo118 [61]

Answer:

x = ±4 (x = 4 and x = -4)

Step-by-step explanation:

4x²-16 = x²+32

3x²-16 = 32

3x² = 48

x² = 16

x = ±4

Therefore, x = 4 and x = -4

5 0
3 years ago
5. Evaluate the function for the given variables.
UkoKoshka [18]

Answer:

C. f(5) = 13 and f(-3) = -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 2x + 3

x = 5

x = -3

<u>Step 2: Evaluate</u>

x = 5

  1. Substitute:                    f(5) = 2(5) + 3
  2. Multiply:                        f(5) = 10 + 3
  3. Add:                              f(5) = 13

x = -3

  1. Substitute:                    f(-3) = 2(-3) + 3
  2. Multiply:                        f(-3) = -6 + 3
  3. Add:                              f(-3) = -3
7 0
3 years ago
Read 2 more answers
Which best explains why the equation 3x+8=3x-5 has no solutions?
tekilochka [14]
3x + 8 = 3x - 5
3x - 3x + 8 = -5
8 = -5 (incorrect)
this means there is no solution, because whatever number u sub in for x, it will not come out true
6 0
3 years ago
Read 2 more answers
Given: AB ∥ DC
RSB [31]

Answer:

A=1,720.16\ units^2

Step-by-step explanation:

we know that

The area of the trapezoid is equal to

A=\frac{1}{2}(DC+AB)DE

step 1

Find the measure of angle DAE

m∠ADC+m∠DAE=180° -----> by consecutive interior angles

we have

m∠ADC = 134°

substitute

134°+m∠DAE=180°

m∠DAE=180°-134°=46°

step 2

In the right triangle ADE

Find the length side AE

cos(∠DAE)=AE/AD

AE=cos(46\°)(40)\\AE=27.79\ units

step 3

In the right triangle ADE

Find the length side DE

sin(∠DAE)=DE/AD

DE=sin(46\°)(40)\\DE=28.77\ units

step 4

Find the area of ABCD

A=\frac{1}{2}(DC+AB)DE

we have

DC=32\ units\\AB=DC+2(AE)=32+2(27.79)=87.58\ units\\DE=28.77\ units

substitute

A=\frac{1}{2}(32+87.58)28.77

A=1,720.16\ units^2

5 0
4 years ago
Solve for x, if 2x-5=7
Zigmanuir [339]
2x-5=7
2x=7+5
2x=12
X=12/2
X=6

Hope this helps!
7 0
4 years ago
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