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Morgarella [4.7K]
3 years ago
11

PLEASE HELP!! What is 6.746913 rounded to the nearest tenths place?

Mathematics
2 answers:
Maslowich3 years ago
7 0

6.746913

Since 3 is less than 5 it drops: 6.74691

Since 1 is less than 5 it drops: 6.7469

Since 9 is more than 5 it carries a one over: 6.747

Since 7 is more than 5 it carries a one over: 6.75

Since 5 is equal to 5 it carries a one over: 6.8

The answer is 6.8

Andrew [12]3 years ago
3 0

If the number is less than 5, round down, if it's equal to or greater than 5, round up.

6.746913

Look to the number to the right of the tenths place.

the number is 4

4 is less that 5 so round down.

The answer would be 6.7


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F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
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Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

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