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3 years ago

PLEASE HELP!! What is 6.746913 rounded to the nearest tenths place?

Mathematics

2 answers:

Maslowich3 years ago

7 0

6.746913

Since 3 is less than 5 it drops: 6.74691

Since 1 is less than 5 it drops: 6.7469

Since 9 is more than 5 it carries a one over: 6.747

Since 7 is more than 5 it carries a one over: 6.75

Since 5 is equal to 5 it carries a one over: 6.8

The answer is 6.8

Andrew [12]3 years ago

3 0

If the number is less than 5, round down, if it's equal to or greater than 5, round up.

6.746913

Look to the number to the right of the tenths place.

the number is 4

4 is less that 5 so round down.

The answer would be 6.7

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Find the MEDIAN of the data set. (Hint: the numbers must be in order first!) 40 76 40 63 47 57 49 55 50 53

Romashka [77]

Given:

The data set is:

40, 76, 40, 63, 47, 57, 49, 55, 50, 53

To find:

The median of the given data set.

Solution:

We have,

40, 76, 40, 63, 47, 57, 49, 55, 50, 53

Arrange the data values in ascending order.

40, 40, 47, 49, 50, 53, 55, 57, 63, 76

Here, the number of observations is 10 which is an even number. So, the median is:

$Median=\dfrac{(\dfrac{n}{2})\text{th term}+(\dfrac{n}{2}+1)\text{th term}}{2}$

Putting n=10, we get

$Median=\dfrac{(\dfrac{10}{2})\text{th term}+(\dfrac{10}{2}+1)\text{th term}}{2}$

$Median=\dfrac{5\text{th term}+6\text{th term}}{2}$

From the arranged terms, it is clear that the the 5th term is 50 and the 6th term is 53.

$Median=\dfrac{50+53}{2}$

$Median=\dfrac{103}{2}$

$Median=51.5$

Therefore, the median of the given data set is 51.5.

4 0

3 years ago

4. Rewrite the expression using the distributive property.<br> (7•3) + (7•7)

dezoksy [38]

(7•7)+(7•7)

We can use the formula of distributive property
a(b+c)=ab+ac
So it will look like a(b+c)= (7•7)+(7•3)
A is 7, B is also 7, and C is 3. Plug those in and you get 7(7+3)

Answer: 7(7+3)

Hope this helps ʕ•ᴥ•ʔ

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

3 years ago

Express the following in the form p/q , where p and q are integers and q is not equal to 0<br> 0.47

Gennadij [26K]

Given,
0.47
X= 0.47
10x = 4.7

100x = 47.7

90X = 43

X = 43/90

p/q= 43/90

4 0

3 years ago

THIS IS DUE TOMORROW<br>HELP

sukhopar [10]

Answer:

Step-by-step explanation:

4) 35x + 28y =7*5*x + 7*4*y = 7(5x + 4y)

5) Cost of top = $9

Cost of 3 top = 9*3 = $27

Cost of skirt = $x

Cost of 3 skirt = 3x

Cost of 3 skirt and 3 top = 3x + 27

Cost of 2 skirt = 2x (as she bought 5 skirts)

Cost of her purchase = Cost of 3skirt &3 top and 2skirt

= (3x + 27) + 2x

= 5x +27

6) Cost of 5 nail polish bottle = 5p

Cost of two lip gloss tube = 2g

Cost of one gift bag = 5p + 2g

Cost of 8 gift bag = 8* ( 5p + 2g)

=8*5p + 8*2g

= 40p + 16g

8 0

4 years ago