Question

Write an equation in standard form for each parabola.​

Answer 1

Answer:

$x=1/4(y-2)^{2}-1$

Step-by-step explanation:

Use Vertex form: $x=a(y-k)^{2}+h$

Given: vertek (h, k)=(-1, 2)  

$x=a(y-2)^2 -1$

A point:(x , y) = (3, 6)

$3 = a (6-2)^{2} -1$

16a=4, a=1/4

The equation is : $x=1/4(y-2)^{2}-1$