I couldn't format this properly from my phone, so I used a solver, sorry :( hope this helps tho...
Using the given information, the width of the river is 505.96 m
<h3>Bearing and Distances</h3>
From the question, we are to determine the width of the river
Consider the given diagram,
Let F be the first position of the biker
S be the second position
and C be the position of the church
First, we will determine the distance covered from F to S
Speed = 160m/min
Time = 4 minutes
Using the formula,
Distance = Speed × Time
Distance covered = 160 × 4
Distance covered = 640 m
That is, /FS/ = 640 m
Now, consider ΔFSC
∠F = 90° - 70° = 20°
∠S = 90° + 56° = 146°
and ∠C = 180° - 20° - 146° = 14°
By the Law of Sines

∴ 

/FC/ = 1479.33 m
Now,
By SOH CAH TOA

NOTE: d is the width of the river
∴ d = /FC/ × cos70°
d = 1479.33 × cos70°
d = 505.96 m
Hence, the width of the river is 505.96 m
Learn more on Bearing and distances here: brainly.com/question/19351991
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Here you will divide 500 by 6 to get the girl students, and 500 by 5 to get boys.
Answer:
D
Step-by-step explanation:
let me know if its correct
Answer:
=
(3n + 7)
Step-by-step explanation:
We require to find the first term a₁ and the common difference d
The n th term is given by 3n + 2, thus
a₁ = 3(1) + 2 = 3 + 2 = 5
a₂ = 3(2) + 2 = 6 + 2 = 8
d = 8 - 5 = 3
=
[ 2a₁ + (n - 1)d ], substitute values
=
[ (2 × 5) + 3(n - 1) ] =
(10 + 3n - 3) =
(3n + 7)