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Semmy [17]
3 years ago
13

How do you solve for x: -(4 - x) = 3/4 (x - 6)?

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0
I honestly don’t know I am just doing this because I need to ask a question hope I helped
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Factor the greatest common factor: 9a4b3 + 24a3b2 − 15a2b.
skelet666 [1.2K]
I couldn't format this properly from my phone, so I used a solver, sorry :( hope this helps tho...

4 0
3 years ago
You are riding along a straight river from east to the west at speed of 160m/m. At a given time, you will see the bearing of a c
yuradex [85]

Using the given information, the width of the river is 505.96 m

<h3>Bearing and Distances</h3>

From the question, we are to determine the width of the river

Consider the given diagram,

Let F be the first position of the biker

S be the second position

and C be the position of the church

First, we will determine the distance covered from F to S

Speed = 160m/min

Time = 4 minutes

Using the formula,

Distance = Speed × Time

Distance covered = 160 × 4

Distance covered = 640 m

That is, /FS/ = 640 m

Now, consider ΔFSC

∠F = 90° - 70° = 20°

∠S = 90° + 56° = 146°

and ∠C = 180° - 20° - 146° = 14°

By the Law of Sines

\frac{/FC/}{sin\ S}= \frac{/FS/}{sin\ C}

∴ \frac{/FC/}{sin\ 146^\circ}= \frac{640}{sin\ 14^\circ}

/FC/ =\frac{640 \times sin \ 146^\circ}{sin \ 14^\circ}

/FC/ = 1479.33 m

Now,

By SOH CAH TOA

cos \ 70^\circ = \frac{d}{/FC/}

NOTE: d is the width of the river

∴ d = /FC/ × cos70°

d = 1479.33 × cos70°

d = 505.96 m

Hence, the width of the river is 505.96 m

Learn more on Bearing and distances here: brainly.com/question/19351991

#SPJ1

7 0
2 years ago
Montgomery Middle School has a ratio of 6 girls for every 5 boys. If Montgomery Middle School has 500 students, how many of thei
sveticcg [70]
Here you will divide 500 by 6 to get the girl students, and 500 by 5 to get boys.
7 0
3 years ago
State the relationship between the graphs of f(x) and g(x).
AfilCa [17]

Answer:

D

Step-by-step explanation:

let me know if its correct

4 0
3 years ago
If the nth term of an A.P. is 3n+2, find the sum of first 'n terms of that AP.​
alexdok [17]

Answer:

S_{n} = \frac{n}{2} (3n + 7)

Step-by-step explanation:

We require to find the first term a₁ and the common difference d

The n th term is given by 3n + 2, thus

a₁ = 3(1) + 2 = 3 + 2 = 5

a₂ = 3(2) + 2 = 6 + 2 = 8

d = 8 - 5 = 3

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ], substitute values

S_{n} = \frac{n}{2} [ (2 × 5) + 3(n - 1) ] = \frac{n}{2} (10 + 3n - 3) = \frac{n}{2} (3n + 7)

6 0
4 years ago
Read 2 more answers
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