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Vika [28.1K]
3 years ago
15

For which values of P and Q does the following equation have infinitely many solutions ?

Mathematics
1 answer:
solmaris [256]3 years ago
4 0

Answer:

(P, Q) = (-75, 57)

Step-by-step explanation:

The equation will have infinitely many solutions when it is a tautology.

Subtract the right side from the equation:

Px +57 -(-75x +Q) = 0

x(P+75) +(57 -Q) = 0

This will be a tautology (0=0) when ...

P+75 = 0

P = -75

and

57-Q = 0

57 = Q

_____

These values in the original equation make it ...

-75x +57 = -75x +57 . . . . . a tautology, always true

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A local school has was evaluated the the Education Department and received the
Angelina_Jolie [31]

Answer: 79

Step-by-step explanation:

Given the following :

Graduation Rates:

Grade:82

Weight: 50%

Passing Rates:

Grade: 75

Weight: 30%

Enrollment Numbers:

Grade: 60

Weight: 10%

Career readiness:

Grade: 95

Weight: 10%

Overall score : Σ(grade × weight)

(82 × 50%) + (75 × 30%) + (60 × 10%) + (95 × 10%)

= (41 + 22.5 + 6 + 9.5)

= 79

Hence, overall score is 79

5 0
3 years ago
what is the perimeter of the triangle. i do not know how to start this problem. any help will be greatly appreciated :))
xz_007 [3.2K]

Given:

Point F,G,H are midpoints of the sides of the triangle CDE.

FG=9,GH=7,CD=24

To find:

The perimeter of the triangle CDE.

Solution:

According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.

FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get

\dfrac{1}{2}DE=FG

DE=2(FG)

DE=2(9)

DE=18

GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get

\dfrac{1}{2}CE=GH

CE=2(GH)

CE=2(7)

CE=14

Now, the perimeter of the triangle CDE is:

Perimeter=CD+DE+CE

Perimeter=24+18+14

Perimeter=56

Therefore, the perimeter of the triangle CDE is 56 units.

7 0
3 years ago
PLEASE HELP QUESTION ATTACHED
Bess [88]
Point S is the answer 

move -2.25 on the x axis and 2/3 on the y form the origin

3 0
3 years ago
Which of the following could be the lengths of the sides of a 30°-60°-90° triangle?
Inga [223]
According to Pythagoras theorem

a^2+b^2=c^2

similarly ,

3^2+ 4^2= 5^2

9+16=25
25=25

LHS=RHS
so angle of triangle is 30 , 60 and 90

answer is 3,4,5
7 0
3 years ago
Read 2 more answers
Help, please what do I need to do ?
GREYUIT [131]
Find the hypotenuse JL.
3.6^2 + 4^2 = 12.96+16=28.96
Square root it. =5.4

There you go. 5.4 is the radius
4 0
3 years ago
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