Answer: 79
Step-by-step explanation:
Given the following :
Graduation Rates:
Grade:82
Weight: 50%
Passing Rates:
Grade: 75
Weight: 30%
Enrollment Numbers:
Grade: 60
Weight: 10%
Career readiness:
Grade: 95
Weight: 10%
Overall score : Σ(grade × weight)
(82 × 50%) + (75 × 30%) + (60 × 10%) + (95 × 10%)
= (41 + 22.5 + 6 + 9.5)
= 79
Hence, overall score is 79
Given:
Point F,G,H are midpoints of the sides of the triangle CDE.

To find:
The perimeter of the triangle CDE.
Solution:
According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.
FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get




GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get




Now, the perimeter of the triangle CDE is:



Therefore, the perimeter of the triangle CDE is 56 units.
Point S is the answer
move -2.25 on the x axis and 2/3 on the y form the origin
According to Pythagoras theorem
a^2+b^2=c^2
similarly ,
3^2+ 4^2= 5^2
9+16=25
25=25
LHS=RHS
so angle of triangle is 30 , 60 and 90
answer is 3,4,5
Find the hypotenuse JL.
3.6^2 + 4^2 = 12.96+16=28.96
Square root it. =5.4
There you go. 5.4 is the radius