Ask question

Ask question

All categories

3 years ago

12

How to graph equasions

1 answer:

saw5 [17]3 years ago

4 0

Hi there :) The best way to graph equations and to follow these 3 steps

<span>1. Locate the y-intercept on the graph and plot the point.
2. From this point, use the slope to find a second point and plot it.
3. Draw the line that connects the two points.

Please mark brainliest, thanks!</span>

You might be interested in

Type the correct answer in the box. Use numerals instead of words.

aleksley [76]

Answer:

28080$

Step-by-step explanation:

there are 52 weeks in a year.

15x10= 150

150x52=7800

13x30= 390

390x52= 20280

20280+7800= 28080

7 0

3 years ago

There are 4 second grade classrooms that share 15 packs of paper. How much paper should each classroom get?

shusha [124]

Answer:

3.75 packs

Step-by-step explanation:

15/4=3.75 packs

7 0

3 years ago

Find the x intercept of the graph of the equation -2(x+1)^2 +18

Burka [1]

Answer:

x=2, -4

Step-by-step explanation:

The equation is $y=-2(x+1)^2 +18$ . The x-intercept is the point(s) where the function intersects the x axis, so this value can be found by plugging in 0 for y. doing so results in $0=-2(x+1)^2 +18$ . Then, solve for x by moving 18 over, dividing by -2, square rooting both sides, and subtracting 1 to find the value of x.

8 0

3 years ago

Read 2 more answers

What is the equation of the line that passes through (-2,3) and is parallel to 2x+3y=6?

Vsevolod [243]

Answer:

<h2>2x + 3y = 5</h2>

Step-by-step explanation:

$\bold{METHOD\ 1:}$

The slope-intercept form of an equation of a line:

$y=mx+b$

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

Let $k:y=m_1x+b_1,\ l:y=m_2x+b_2$

then

$l\ \parallel\ k\iff m_1=m_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}$

We have the equation of a line:

$2x+3y=6$

Convert to the slope-intercept form:

$2x+3y=6$ <em>subtract 2x from both sides</em>

$3y=-2x+6$ <em>divide both sides by 3</em>

$y=-\dfrac{2}{3}x+2\to m_1=-\dfrac{2}{3}$

therefore the slope is $m_2=-\dfrac{2}{3}$

Put the value of the slope and the coordinates of the point (-2, 3) to the equation of a line:

$3=-\dfrac{2}{3}(-2)+b$

$3=\dfrac{4}{3}+b$ <em>subtract 4/3 from both sides</em>

$\dfrac{9}{3}-\dfrac{4}{3}=b\to b=\dfrac{5}{3}$

Finally:

$y=-\dfrac{2}{3}x+\dfrac{5}{3}$

Convert to the standard form (Ax + By = C):

$y=-\dfrac{2}{3}x+\dfrac{5}{3}$ <em>multiply both sides by 3</em>

$3y=-2x+5$ <em>add 2x to both sides</em>

$2x+3y=5$

$\bold{METHOD\ 2:}$

Let $k:A_1x+B_1y=C_1,\ l:A_2x+B_2y=C_2$ .

Lines <em>k</em> and <em>l</em> are parallel iff

$A_1=A_2\ \wedge\ B_1=B_2\to\dfrac{A_2}{A_1}=\dfrac{B_2}{B_1}$

We have the equation:

$2x+3y=6\to A_1=2,\ B_1=3$

then the equation of a line parallel to given lines has the equation:

$2x+3y=C$

Put the coordinates of the point (-2, 3) to the equation:

$C=2(-2)+3(3)\\\\C=-4+9\\\\C=5$

Finally:

$2x+3y=5$

4 0

3 years ago

What percentage (nearest whole percent) is budgeted for entertainment if $200 is allotted from a total budget of $1260 ?

ira [324]

200/1260= .15873
Answer:16%

7 0

3 years ago