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Dmitry_Shevchenko [17]
3 years ago
9

Can you please help me with this? 14 + 5(x + 3) - 7x

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0
You multiply 5,x,3 and y will get 5x+15.Then you add 7x and 5x  and you get 12x. Finally you subtracted 15&14 and get 1 then you divide 12x from 1 and get 12.
TEA [102]3 years ago
4 0
Well first you have to do distributive property with the parenthesis, multiply 5 times x and 5 times 3 to get 5x and 15 now you have 14+5x+15-7x, now add common like terms(these are terms taht have the same number variable or both) so your common numbers will be 14 and 15, and 5x and -7x now add or subtract them to get -2x+29 now you have to set x by itself so set this binomial equal to 0 to get -2x+29=0 subtract the 29 from both sides and get -2x=-29 now divide 2 by both sides to get x=29/2

Hope this helps
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7 0
3 years ago
Please help with geometry
olga_2 [115]

Presumably l and m are parallel, so n and p are transversals across parallel lines.  They'll make the obvious congruent angles and supplementary angles (add to 180 degrees) that presumably the questions will be asking about.

1. Angle 11 and angle 16.   They're what's called vertical angles from a pair of crossing lines.  Vertical angles are congruent, so m∠16 = 113°

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5x + 2 = 3x + 28

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x = 13

5 0
3 years ago
choose the slope-intercept equation of the line that passes through the point (4, -6) and is parallel to y = - 1/2x 5. a. y = -2
nexus9112 [7]
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4 0
4 years ago
Read 2 more answers
What are five costs related to business?
ANTONII [103]

Answer:

Advertising and promotion.

Borrowing costs.

Employee expenses.

Equipment and supplies.

Insurance, license, and permit fees.

Research expenses.

Technological expenses.

Step-by-step explanation:

7 0
3 years ago
The initial value of a quantity Q (at year t = 0) is 112.8 and the quantity is decreasing by 23.4% per year. a) Write a formula
Svetach [21]

Answer:

a) Q(t) = 112.8*(0.766)^{t}

b) When t = 10, Q = 7.845.

Step-by-step explanation:

The value of a quantity after t years is given by the following formula:

Q(t) = Q_{0}(1 + r)^{t}

In which Q_{0} is the initial quantity and r is the rate that it changes. If it increases, r is positive. If it decreases, r is negative.

a) Write a formula for Q as a function of t.

The initial value of a quantity Q (at year t = 0) is 112.8.

This means that Q_{0} = 112.8.

The quantity is decreasing by 23.4% per year.

This means that r = -0.234

So

Q(t) = 112.8*(1 - 0.234)^{t}

Q(t) = 112.8*(0.766)^{t}

b) What is the value of Q when t = 10?

This is Q(10).

Q(t) = 112.8*(0.766)^{t}

Q(t) = 112.8*(0.766)^{10} = 7.845

When t = 10, Q = 7.845.

4 0
4 years ago
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