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drek231 [11]
4 years ago
14

Two students from a group of 8 boys and 12 girls are sent to represent the group in a school parade. If two students are chosen

at random, what is the probability that both students are girls?
Mathematics
2 answers:
Karo-lina-s [1.5K]4 years ago
8 0

Answer: 33/95

Step-by-step explanation:

Just did the test. Got it right

DIA [1.3K]4 years ago
4 0

Answer:

33/95 or 34.74 %

Step-by-step explanation:

total # of kids = 20

chance first student would be a girl: 3/5

chance second student would be a girl: 11/19

3/5 × 11/19 = 33/95

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A has a piece of ribbon that is one fourth long she wants to share the ribbon with 2 friends so that they can each wear a ribbon
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How long is the ribbon? Or in other words what is it 1/4 of?
5 0
4 years ago
A) The equilibrium prices P1 and P2 for two goods satisfy the equations:
Allisa [31]

The value of P1 and P2 using the inverse matrix is 5 and 6 respectively.

<h3 />

The equilibrium prices of the three independent commodities using the inverse matrix are P1 = 4, P2 = 7, P3 = 8 respectively.

<h3>What is a matrix?</h3>

A matrix can be defined as a collection of integers(numbers that are either positive or negative) that are organized in rows and columns to construct a rectangular array. The numbers in this matrix system are referred to as elements.

To determine the values of P1 and P2 for the system of equations given by using an inverse matrix, we have:

a)

9P1 + P2 = 51

3P1 +4P2 = 39

Representing the above data in matrix form, we have:

\left[\begin{array}{cc}9&1\\3&4\\ \end{array}\right] \left[\begin{array}{c} \mathbf{P_1} \\ \mathbf{P_2}\\ \end{array}\right] =  \left[\begin{array}{c} \mathbf{51} \\ \mathbf{39} \\ \end{array}\right] which is in the form AX = B

  • In order for us to determine the values of P1 and P2, Let take the inverse of A⁻¹ on both sides of the AX= B, we have:

\mathbf{{A^{-1} AX} = A^{-1} B}

X = A⁻¹ B

Let's start by finding A⁻¹;

\mathbf{A = \left[\begin{array}{cc}9&1\\3&4\end{array}\right] }

\mathbf{A^{-1} = \dfrac{1}{36-3}\left[\begin{array}{cc}4&-1\\3&9\end{array}\right] }

\mathbf{A^{-1} = \dfrac{1}{33}\left[\begin{array}{cc}4&-1\\3&9\end{array}\right] }

Now, Let's Find A⁻¹B;

\mathbf{A^{-1}B = \dfrac{1}{33}\left[\begin{array}{cc}4&-1\\3&9\end{array}\right] \left[\begin{array}{c}51\\39\\ \end{array}\right] }

\mathbf{\implies \dfrac{1}{33}\left[\begin{array}{cc}204&-39\\-153&+351\end{array}\right]  }

\mathbf{\implies \left[\begin{array}{c}\dfrac{165}{33}\\ \\ \dfrac{198}{33}\end{array}\right]  }

\mathbf{\implies \left[\begin{array}{c}5\\ \\ 6\end{array}\right]  }

\left[\begin{array}{c}\mathbf{P_1}\\  \mathbf{P_2}\end{array}\right]= \left[\begin{array}{c}5\\ 6 \end{array}\right] }

Therefore, we can conclude that the value of P1 and P2 using the inverse matrix is 5 and 6 respectively.

b)

To determine the equilibrium prices of the three independent commodities using the inverse matrix, we have:

P₁ + 2P₂ + 3P₃ = 42

2P₁ + P₂ + 4P₃ = 47

P₁ + 3P₂ + 4P₃ = 57

The matrix in AX = B form is computed as:

\implies\left[ \begin{array}{ccc}1&2&3\\2&1&4\\1&3&4\end{array}\right] \left[\begin{array}{c}P_1\\P_2\\P_3  \end{array}\right] = \left[\begin{array}{c}42\\47\\ 57\end{array}\right]

\mathbf{A^{-1} = \dfrac{1}{|A|} \  (adj \  A)}

\mathbf{A^{-1} = \dfrac{1}{1(4-12) -2(8-4) +3(6-1)} \left[\begin{array}{ccc}-8&4&5\\1&1&-1\\5&2&-3\end{array}\right] }^1

\mathbf{A^{-1}B = -1 \left[\begin{array}{ccc}-8&1&5\\-4&1&2\\5&2&-3\end{array}\right] }\left[\begin{array}{c}42\\47\\57\end{array}\right]

\mathbf{A^{-1}B = -\left[\begin{array}{ccc}-336&+47&+285\\-168&+47&+114\\210&-47&-171\end{array}\right] }

\mathbf{A^{-1}B = -\left[\begin{array}{c}-4\\-7\\-8\end{array}\right] }

\mathbf{A^{-1}B = \left[\begin{array}{c}4\\7\\8\end{array}\right] }

Therefore, we can conclude that the values of P1 = 4, P2 = 7, P3 = 8 respectively.

Learn more about matrix here:

brainly.com/question/1821869

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4x+12y=-16 solve for y show work
defon

Answer:

u mean make y the subject

Step-by-step explanation:

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3 years ago
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The total cost of a printer is $510. If the cost of the computer is 13/4 the cost of the printer, find the price of each. ( in e
vivado [14]

Answer:printer=120$

computer=390$

Step-by-step explanation:

printer=x

computer=x × 13/4

x+x × 13/4=510

(4x+13x)/4=510

17x=510×4

x=2040÷17

x=120

y=120×13/4

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4 years ago
4.22 x 1o^6 + 2.25 x 10^5 + 2.8 x 10^6
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