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Alexxandr [17]
4 years ago
10

WILL GIVE BRAINLIEST

Mathematics
2 answers:
Genrish500 [490]4 years ago
8 0

Answer:A 0

Step-by-step explanation:

Zigmanuir [339]4 years ago
4 0
Answer:A. Just took the test
.


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I need to know the surface area of these
anastassius [24]

9514 1404 393

Answer:

  245 cm²

Step-by-step explanation:

The surface area of a cone is given by ...

  SA = πr(r +s) . . . . where r is the radius, and s is the slant height

Filling in the given values, we have ...

  SA = (3.14)(3 cm)(3 cm +23 cm) = (3.14)(3)(26) cm² ≈ 245 cm²

The surface area of the cone is about 245 cm².

6 0
3 years ago
A badminton tournament begins with 512 teams. If a team loses once, it is eliminated from competition. After the first round, 25
tankabanditka [31]

Answer:

This is GP with the first term of 512 and common ratio of 1/2

<u>The formula for nth term is:</u>

  • aₙ = 512*(1/2)ⁿ

<u>The number of teams after the 4th round:</u>

  • a₄ = 512*(1/2)⁴ = 32 teams

<u>Number of rounds to determine the champion:</u>

  • 1 = 512*(1/2)ⁿ
  • 2⁰ = 2⁹*2⁻ⁿ
  • 0 = 9 - n
  • n = 9 rounds
8 0
3 years ago
Read 2 more answers
PLZZ HELPP IM FAILLING THIS CLASS
Nataly_w [17]

Answer:

Well thats not good

Step-by-step explanation:

is this a test? i like tests.

6 0
3 years ago
In one statistics course, students reported studying an average (mean) of 9.92 hours a week, with a standard deviation of 4.54.
quester [9]

Answer:

For the student who is studying 10 hours a week is in the 57.93th percentile.

Step-by-step explanation:

Corresponding z-score for the student who studies 10 hours a week can be calculated by the formula

z=\frac{x-M}{s} where

  • x is the hours student work in a week, which is 10,
  • M is the mean studying hour of the class, which is 9.92,
  • s is the standart deviation which is 4.54

from here we find that z=\frac{10-9.92}{4.54}≈0.2

Corresponding percentile for z=0.2 is 57.93

6 0
4 years ago
PlS HELPPPP BRAINLIESTT IF GOOD
zimovet [89]

Answer:

D. r=-1 is the correlation coefficient

7 0
3 years ago
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