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kogti [31]
3 years ago
8

The numbers 1, 2, 3, and 4 have weights 0.1, 0.2, 0.3, and 0.4 respectively. Compute the weighted average. (to the nearest tenth

)
es )
Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer:

3.0

Step-by-step explanation:

1(0.1) + 2(0.2) + 3(0.3) + 4(0.4) = 3.0

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A rectangular garden has an area of 360 square feet. the length of the garden is 9 feet longer than the width. find the dimensio
rosijanka [135]

\huge\underline{\frak{  \:  \:  \:  \:  \:  \: Solution : \:  \:  \:  \:  \:  \: }} \\  \\

\frak {\pink{Let}}\begin{cases} \sf{\red{Breadth \:  be  \: x}}\\ \sf{\orange{The \:  Length = x + 9}}\end{cases} \\

\bigstar \: \underline{\textsf{According to the given Question :} }\\  \\

:\implies \sf Area = Length \times Breadth \\  \\  \\

:\implies \sf 360=(x + 9 ) x \\  \\  \\

:\implies \sf 360= {x}^{2} + 9x  \\  \\  \\

:\implies \sf  {x}^{2}   + 9x - 360 = 0\\  \\  \\

:\implies \sf  {x}^{2}   + 24x - 15x - 360 = 0\\  \\  \\

:\implies \sf  x(x + 24) - 15(x + 24) = 0\\  \\  \\

:\implies \sf (x + 24) \: (x - 15) = 0\\  \\  \\

:\implies \underline{ \boxed{ \sf  x =  - 24 \: or \: x = 15}}\\  \\  \\

\therefore\:\underline{\textsf{Ignoring the negative value, the Breadth of rectangular garden is \textbf{15 ft}}}. \\  \\  \\

<h2>_____________________...</h2>

\bigstar \: \underline{\textsf{Dimensions of rectangular garden :}} \\  \\

\bullet\:\:\textsf{The Breadth of rectangular garden = x = \textbf{15 ft.}} \\  \\

\bullet\:\:\textsf{The Length of rectangular garden = x + 9 = 15 + 9 = \textbf{24 ft.}} \\  \\

6 0
3 years ago
HELP ASAP PLEASE, this is the last question i promise T^T
Vikentia [17]

Answer:

A= 10

Step-by-step explanation:

[10 + 2/360˚(10)]

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Step-by-step explanation:

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B. lie in the same plane
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