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Scorpion4ik [409]
3 years ago
15

Which of the integers shown is the greatest? -22 -5 -7 or -3

Mathematics
1 answer:
KonstantinChe [14]3 years ago
5 0

Answer:

-3

Step-by-step explanation:

the larger the integer the smaller the value

so -22 is actually the smallest value

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Answer:

Rule:

f(n)=2(4)^n

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Read 2 more answers
Determine which ordered pairs fall on the graph of f(x) = -2x-1 Show all of your work for each ordered pair. Ordered Pairs: (1,1
LiRa [457]

Answer:

(1, 1) is the only one on the graph

Step-by-step explanation:

To determine if an ordered pair lies on the graph, substitute the x-coordinate of the ordered pair into f(x) and evaluate. If the value equals the y-coordinate of the ordered pair then it lies on the graph

f(1) = (2 × 1) - 1 = 2 - 1 = 1 ⇒ (1, 1) lies on graph

f(- 1) = (2 × - 1) - 1 = - 2 - 1 = - 3 ≠ - 4 ⇔ (- 1, - 4 ) not on graph

f(- 2) = (2 × - 2) - 1 = - 4 - 1 = - 5 ≠ - \frac{1}{8} ⇒ (- 2, - \frac{1}{8}) not on graph

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8 0
4 years ago
Plssss help i really need this done urgent​
dem82 [27]

Answer:

Images are neither similar nor congruent.

Coordinates of (-3,2) when transformed are (-6, 8).

Step-by-step explanation:

In the transformation we are multiplying the coordinates by two different numbers (2 for x, 4 for y ); therefore the transformed figure can neither be similar nor congruent.

This is because a transformation that results in a congruent figure must of of the form (x\pm a, y\pm a)—this is just shifting the figure.

The transformation that results in a similar figure must be of the form (ax,ay) or a(x,y)—this is just scaling the figure.

Since the transformation (2x,4y)  is neither a congruent transformation nor a similar transformation ,the resulting figure in neither similar nor congruent.

The point (-3, 2) transforms to

(-3,2)\rightarrow (2(-3), 4(2))=\boxed{(-6,8)}

3 0
3 years ago
Quick!!!<br> If the side lengths of a triangle are 23, 16, and 7; what type of triangle is it?
ololo11 [35]
<h3>No it does not form a triangle!~</h3>

Let's prove it by pythogoras theorem,

  • Hypotenuse = 23
  • Base = 7
  • Perpendicular = 16

\bf \: H^{2} =P^{2} +B^{2}

\sf \:  {23}^{2}  =  {16}^{2}  +  {7}^{2}

\sf \: 529 = 256 + 49

\sf \: 529  \cancel= 305

<h3>Hence (Proved) </h3>
7 0
2 years ago
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