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You just multiply by 2 as you can see
4×2=8
8×2=16 and so on
64×2=128 therefore 128 is the answer
Answer:
(-ab^2)^3.
Step-by-step explanation:
-a^3b^6 = (-ab^2)^3
Answer:
The easiest way to get this is through divide and conquer.
Therefore take 1, 2, 3, 5, 7, 9, and 11.
1 is a factor obviously.
2 is a factor since 80 is divisible by 80. We found a factor so divide the value 80 by 2 and we get 40. Is 2 a factor of 40? Yep, so divide again and we have 20. Is 2 a factor of 20. Yep. So is 10. So now we are at 5. But 5 is not a factor of 2. 5 is a factor of 5.
So we have the following 1, 2, 2, 2, 2, and 5. Thus 2 and 5 are your prime factors of 80. Note this is NOT the prime factorization of the number 80. That value is 2^4 * 5. You asked the prime factors of 80. Those are 2 and 5.
Hope this helped good luck
-Emily
