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3 years ago

Find the x- and y- intercepts if they exist 3x+5y=12

Mathematics

2 answers:

kifflom [539]3 years ago

6 0

The answer of the x and y intercepts is
x=(4,0)
y=(0, 12/5)

choli [55]3 years ago

3 0

Answer:

Y= -3/5x+12/5

X= -5/3+4

Step-by-step explanation:

I am not sure if this is what you were looking for but it might be useful.

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Simplify the expression.(–12m 38)

Ludmilka [50]

-6m+19
1/2(-12m+38) All we have to do is simply distribute the 1/2. 1/2(-12m) + 1/2(38) (-6m) + 19

5 0

3 years ago

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Write the digits in the thousands place

Sloan [31]

What digits? is there specific types?

6 0

2 years ago

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Maurice buys a dozen of donuts on sale for $7.99 before tax.

adoni [48]

Answer:

$8.30

Step-by-step explanation:

7.99 + 4% = 8.30

5 0

2 years ago

If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that

Ivan

Answer:

$\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}$

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

Given :-

• $\sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}$

To Prove :-

• $\sf\implies cos2A =\dfrac{\sqrt3}{2}$

Proof :-

We know that ,

$\sf\implies cos2A = 1 - 2sin^2A$

Therefore , here substituting the value of sinA , we have ,

$\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2$

Simplify the whole square ,

$\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}$

Add the numbers in numerator ,

$\sf\implies cos2A = 1-2\times \dfrac{4-2\sqrt3}{8}$

Multiply it by 2 ,

$\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}$

Take out 2 common from the numerator ,

$\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}$

Simplify ,

$\sf\implies cos2A = 1 -\dfrac{ 2-\sqrt3}{2}$

Subtract the numbers ,

$\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}$

Simplify,

$\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }$

Hence Proved !

8 0

2 years ago

What is the sum of the first 40 odd integers greater than zero?

marusya05 [52]

The answer you are looking for is 339

5 0

3 years ago