All categories

2 years ago

What is the probability that john and alex are born on tuesday?

Mathematics

2 answers:

lord [1]2 years ago

7 0

S(1/7)(1/7)= 1/49

7 days in a week one Tuesday in 7 days for each

Svet_ta [14]2 years ago

5 0

1.5% percent for them both Robb's born on the same day

You might be interested in

Help me please i put 15 points i think that means it gives you 7 or 8 points??

castortr0y [4]

Answer:

Mean: 0.15125

Median: 0.05

Mode: .05

Range: 0.495

Hope this helps!

3 0

3 years ago

Least to greatest -14,10,12,-6,-8,-9,13

tatyana61 [14]

Answer: -14, -9, -8, -6, 10, 12, 13

Step-by-step explanation: Think of all the numbers money. The negative ones mean that you owe people money so the bigger the negative number is the more you owe people which is the less money you have.

6 0

3 years ago

Read 2 more answers

A carpenter uses 12 nails for each board. If there are 48 nails in a pound, how many pounds would be used for 100 boards?

erica [24]

There would be 25 pounds of nails.

3 0

3 years ago

Help help help help help help help help

djyliett [7]

Answer:

Option A is correct

Step-by-step explanation:

6 feet 2 inches = 74 inches

74 inches = $6 \frac{1}{6}$ feet.

<h3>Hope it is helpful....</h3>

8 0

2 years ago

Read 2 more answers

Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

5 0

3 years ago