Assuming width=diameter
diameter/2=radius
area=hpir^2
w=d=2
d/2=2/2=1=r
h=6
area=6pi1^2
area=6pi1
area=6pi
aprox pi=3.141592
area=18.85 cm³
Given:
The function is
To find:
The zeros of the given function.
Solution:
The general form of polynomial is
...(i)
where, a is a constant, 
are zeros of respective multiplicities 
.
We have,
On comparing this with (i), we get
It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.
Therefore, the correct option is B.
f(5) means to replace x in the equation with 5 then solve.
f(x) = x^2 +2x
f(5) = 5^2 + 2(5)
f(5) = 25 +10
f(5) = 35
The answer is D)35
2×6 ones= 12 ones
2× 4 tens(40)=80(8 tens)
tens(10)+1 ten=20(2 tens)
2×3 hundreds(300)=600(6 hundreds)
(if 2 is a square)
6xy ( x2 - xy + y2)
= 6x3y - 6x2y2 - 6xy3 --------------the threes and twos on this line are squares and cubics. the six is just a whole number
