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Elza [17]
3 years ago
7

How do you do 11-2(3m-10)=5(4-m)

Mathematics
1 answer:
Nastasia [14]3 years ago
4 0

Exact Form:

m= 69/19

Decimal Form:

m=3.63157894…

Mixed Number Form:

m= 3 12/19

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In the figure, triangle ABC is congruent to triangle ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', what
snow_tiger [21]
Its 4:1 hope this helps you out.
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3 years ago
Find the value of b. Round your answer to the nearest tenth.
marissa [1.9K]

Answer:

Side CA = 7.8

Step-by-step explanation:

<u>Given:</u>

Acute angled \triangle ABC.

\angle B =40^\circ

AB = 10

BC = 12

We can use cosine rule here to find the side AC = b

<em>Formula for cosine rule: </em>

cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

cos 40 = \dfrac{12^{2}+10^{2}-b^{2}}{2\times 12\times 10}\\\Rightarrow cos 40 = \dfrac{144+100-b^{2}}{240}\\\Rightarrow 0.77 = \dfrac{244-b^{2}}{240}\\\Rightarrow 244-b^{2} = 0.77 \times 240\\\Rightarrow 244-b^{2} = 183.85\\\Rightarrow 244-183.85 = b^{2}\\\Rightarrow b^2 = 60.15\\\Rightarrow b = 7.76

To the nearest tenth <em>b = 7.8</em>

8 0
3 years ago
Tonya has a wastebasket shaped as a cylinder. The wastebasket measures 20 inches tall and has a radius of 5 inches. 
love history [14]
The amount of space left with the snakd container inside the wastebasket=
=(volume of the wastebasket) - (volume of the sanak container)

Volume (cylinder)=area of the circle * height

1) We calculate the volume of a wastebasket:
area of the circle=πr²=π(5 in)²=25π in²
heigth=20 in.

Volume=25π in² * 20 in=500π in³.

2) we calculate the volume of the snack container:
area of the circle=πr²=π(4 in)²=16π in²
heigth=6 in.

Volume=16π in² * 6 in=96π in³

3) we calculate the amount of space left with the sanak container inside the wastebasket.

amount of space left=500π in³ - 96π in³=404π in³

404π in³=404 * 3.141592654...in³≈1269.2 in³

Answer: 404π in³    or  ≈1269.2 in³
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