How would you write 7/10 as a percent using the algorithm method?

Irina-Kira [14]

Answer:

To order fractions from least to greatest, start by finding the lowest common denominator for all of the fractions. Next, convert each of the fractions by dividing the lowest common denominator by the denominator and then multiplying the top and bottom of the fraction by your answer.

Step-by-step explanation:

Hope this helps ❤️

5 0

3 years ago

Any help towards finding out Part B and C would be greatly appreciated!

Alika [10]

Part B: I think the relation that has the greater value when x=6 is f(x) = 7x - 15 because:

7(6) - 15 = 27 which is greater than the output of 14.

Part C: the value of x would be 3 because:

f(x) = 7x - 15
6 = 7x - 15
+ 15 +15
21 = 7x
3 = x

Sorry if any of this is wrong.

6 0

4 years ago

PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME!!!!!!!! THATS ALL. I WILL GIVE POINTS, FAN, MEDAL. PLEASE, I AM SO BAD AT MATH

aleksandrvk [35]

"measures to the nearest tenth of a pound" tell us to round each of the weights listed to the nearest tenth (since the unit is already pounds, no conversion is needed). What this means is if the second number to the right of the decimal is 5 or greater, then we add 1 to the first number to the right of the decimal (and replace the second number with a zero). With all this said, it's much easier to show you, rather than to try to explain it. :D

4.35 is rounded up to 4.4 because the second number to the right of the decimal is 5.
Packet A = 4.4
Packet B = 4.4
Packet C = 4.5
Packed D = 4.4
The question is asking what the heaviest reading will be, so from the whole list above we pick the highest number which is 4.5 pounds. Notice how the answer is not Packet C, or 4.48 pounds, but 4.5 pounds. It is asking for the reading, not the packet, nor the weight. Hope this helps.

7 0

3 years ago

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If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta$

and so the second derivative is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta$

4 0

3 years ago

Jose is wrapping a stack of 100 coins in a paper holder. Each coin is 1/8 inch thick and has a diameter of 1 inch. How many squa

kodGreya [7K]

Answer:

Jose will need 39.25 square inches of paper to wrap the stack of coins

Explanation:

The resulting figure of a stack of 100 coins will be a right circular cylinder. We assume that Jose wraps around the cylinder (so it means not including the bases). Therefore we are solving for the lateral surface area of the cylinder: LSA = 2πrh.

To solve for height h, we multiply the thickness of the coin 100 times.

h = 100 * 1/8 in = 12.5 inches

Solving for radius r:

r = 1 inch/2 = 0.5 inches

LSA = 2(3.14)(0.5 in)(12.5 in) = 39.25 square inches

8 0

3 years ago

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