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2 years ago

If f(x)4^x-8 and g(x)=5x+6, find (f+g)(x)

Mathematics

1 answer:

Greeley [361]2 years ago

5 0

Answer:

Answer:

The value of (f-g)(x)=4^x-5x-14

Step-by-step explanation:

Given : If f(x) = 4^x-8 and g(x)=5x+6

To find : The value of (f - g)(x)?

Solution :

f(x) = 4^x-8

g(x)=5x+6

We can write, (f-g)(x)=f(x)-g(x)

Substitute the value of f(x) and g(x)

(f-g)(x)=4^x-8-(5x+6)

(f-g)(x)=4^x-8-5x-6

(f-g)(x)=4^x-5x-14

Therefore, The value of (f-g)(x)=4^x-5x-14

Plz mark brainliest

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$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

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(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
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P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

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In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

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