Let x,y,z be those numbers. x+y+z = 12 Since x,y,z are consecutive: y=x+1, and z = x+2 Let's replace y and z by their new values: x+x+1+x+2=12 3x+3=12 You subtract 3 from each side to get variables on a side, and numbers on the other: 3x=9 You divide both sides by 3: x=3
y=x+1 = 3+1 = 4 z=x+2 = 3+2 = 5
So the numbers are 3; 4 and 5.
You can re-check your answers (very important): 3+4+5 = 12 3;4;5 are consecutive numbers. The answer has been approved.