log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
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Answer:
20 dollars
Step-by-step explanation:
sorry if I'm wrong
Take into account the the Earths gravity is 9.8 meters a second
Answer:
y = x+7
Step-by-step explanation:
Assuming all of these numbers are ordered pairs (coordinates) when x is 1 y is 8, when x is 2 y is 9 and so on. If you notice y is going up by 1 every time so it follows that the starting point (y intercept) must be 7. Therefore, our equation will be y = x + 7.
Test it out:
Let x =2
y = 2 + 7 = 9 This matches our coordinate (2,9) so it's correct.
Let x =4
y = 4 + 7 = 11 This matches our coordinate (4,11) so it's correct.
Feel free to try out the rest of the coordinates, but usually 2 is enough to confirm that your equation is correct.
Answer:
86% Decrease
Step-by-step explanation:
3.70 times x= 3.20 3.20 divided by 3.70= 0.86