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Shtirlitz [24]
3 years ago
9

Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).

Mathematics
2 answers:
Zina [86]3 years ago
7 0

we are given

\sqrt{30} *\sqrt{610}

we can radical formula

\sqrt{a} *\sqrt{b}=\sqrt{a*b}

we get

\sqrt{30} *\sqrt{610}=\sqrt{30*610}

\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}

we can  also write as

\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}

\sqrt{30} *\sqrt{610}=10\sqrt{183}............Answer


IgorLugansk [536]3 years ago
6 0

The product of \sqrt {30} and \sqrt {610} is \boxed{\sqrt {18300} } or \boxed{10\sqrt {183} }.

Further Explanation:

The product of two square root numbers can be expressed as follows,

\boxed{\sqrtx  \times \sqrt y  = \sqrt {x \times y} }

Given:

The expression is A = \sqrt {30}  \times \sqrt {610}.

Explanation:

A expression than contain the {n^{th}} root is known as the radical equation.

The symbol of the radical is \sqrt[n]{x}.

The radic and is a number that is in the radical.

The given expression is A = \sqrt {30}  \times \sqrt {610}.

Solve the expression to obtain the product of the numbers.

\begin{aligned}A&= \sqrt {30}\times \sqrt {610}\\&= \sqrt {30 \times 610}\\&= \sqrt {18300}\\&= \sqrt {183 \times 100}\\&= 10\sqrt {183}\\\end{aligned}

The product of \sqrt {30} and \sqrt {610} is \boxed{\sqrt {18300} } or \boxed{10\sqrt {183} }.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Exponents and Powers

Keywords: standard dorm, product, square root 30, square rot 610, express, radical expression, expression, factors, simplest form, square root, radicand, cube root, constant term.

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