All categories

3 years ago

How do i solve -14n = 154

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

8 0

Answer:

n=-11

Step-by-step explanation:

-14n = 154

divide both sides by -14

n=-11

Crank3 years ago

8 0

Answer:

N= -11

Step-by-step explanation:

Divde by -14 on each side

You might be interested in

Is .09 greater then .0003

Vlada [557]

Answer:

Yes

Step-by-step explanation:

For ease, let's multiply these by 10,000.

0.09 • 10,000 = 900.00 = 900

0.0003 • 10,000 = 3.00 = 3

900 is clearly greater than 3. Therefore, 0.09 is greater than 0.0003.

8 0

3 years ago

When is it appropriate to use a pie chart?

Law Incorporation [45]

When solving fractions, and percentages, basically comparing parts from a whole.

4 0

3 years ago

A store sells bags of peanuts in 1 1/4–pound packages. How much does 1/3 a package weigh?

nikklg [1K]

Answer:

a) Weight of 1/3 pack of peanuts = $(1\frac{1}{4} \times \frac{1}{3} )$ pounds.

b) Weight of $(2\frac{1}{3} )$ bag of peanuts is $(2\frac{11}{12})$ pounds.

Step-by-step explanation:

The weight of 1 bag of peanuts = $1\frac{1}{4}$ pounds

Solving the mixed fraction, we get the weight of 1 bag = $1\frac{1}{4} = \frac{5}{4}$ pounds

Now, weight of 1/3 bag = $\frac{\frac{5}{4} }{3 } = \frac{5}{4} \times \frac{1}{3}$

or, the weight of 1/3 pack of peanuts = $(1\frac{1}{4} \times \frac{1}{3} )$ pounds.

Now, the weight of $2\frac{1}{3} = \frac{7}{3}$ bag of peanuts is

$\frac{\frac{5}{4} }{\frac{7}{3} } = \frac{5}{4} \times \frac{3}{7}$

⇒ $\frac{35}{12} = 2\frac{11}{12}$

Hence, the weight of $(2\frac{1}{3} )$ bag of peanuts is $(2\frac{11}{12})$ pounds.

7 0

3 years ago

Suppose that 2 ≤ f ' ( x ) ≤ 3 for all values of x . What are the minimum and maximum possible values of f ( 7 ) − f ( 2 ) ? ≤ f

almond37 [142]

Answer:

10 ≤ f ( 7 ) − f ( 2 ) ≤ 15

Step-by-step explanation:

Integrating the given inequalities along the interval from x = 2 to x = 7 yields the minimum and maximum possible values:

$2 \leq f ' ( x )\leq 3\\\int\limits^7_2 {2} \, dx \leq \int\limits^7_2 {f'(x)} \, dx \leq\int\limits^7_2 {3} \, dx \\\\2*7-(2*2)\leq f(7)-f(2)\leq 3*7-(3*2)\\10\leq f(7)-f(2)\leq 15$

The minimum possible value is 10 and the maximum possible value is 15.

8 0

3 years ago

express the following linear equation in the form of ax+by+c=0 and indicate the value of a,b and c. 2x+3y=-5

jok3333 [9.3K]

Answer:

2x+3y+5=0

a = 2 b = 3 c=5

Step-by-step explanation:

We are asked to express 2x+3y=-5 in the form ax+by+c=0

Add 5 to both sides

2x+3y+5=0

We can now find the values of a, b and c now that the equation is in standard form.

5 0

3 years ago