This
can be solve by simple addition and subtraction. Since the initial water in the
lake is 12 in below the normal starting by march, and it decreased further by 2
¼ in by the end of march and increased by 1 5/8 in by the end of april. So the
net water level is
<span>L
= 12 – 2 ¼ + 1 5/8 = 12 5/8 in below the normal</span>
Answer:
Even
Step-by-step explanation:
I think that it's even because the graph is reapeted, if it's odd, it's going to be like x^3
try it on desmos
The width is 30 because perimeter is 2L+2W. Hope this helps you:)
Since 8 i bigger than 4 you can round the 6 into 7 therefore the answer would be 0.7