Let t = initial number of trees "remove 5 trees at the start of the season" means (t - 5) remain "each remaining tree made 210 oranges for a total of 41,790 oranges" means ( t - 5) * 210 = 41790 Now, you can solve for t: (t-5)(210) = 41790 [just re-writing] 210t - 1050 = 41790 [distribute] 210t = 42840 [add 1050 to each side] t = 204 [divide each side by 210] There were initially 204 trees. After 5 were removed, the remaining 199 produced 210 oranges each for a total of 199*210 = 41790 oranges.
Ok so basically 25 Over 8 is magnitude so you subtract then add
Step-by-step explanation:
log b base a=E
b=a^E
but if your question is
log a base b=E
then we have it as
a=b^E
<h3>
Answer:</h3>
- a_n = -3a_(n-1); a_1 = 2
- a_n = 2·(-3)^(n-1)
<h3>
Step-by-step explanation:</h3>
A) The problem statement tells you it is a geometric sequence, so you know each term is some multiple of the one before. The first terms of the sequence are given, so you know the first term. The common ratio (the multiplier of interest) is the ratio of the second term to the first (or any term to the one before), -6/2 = -3.
So, the recursive definition is ...
... a_1 = 2
... a_n = -3·a_(n-1)
B) The explicit formula is, in general, ...
... a_n = a_1 · r^(n -1)
where r is the common ratio and a_1 is the first term. Filling in the known values, this is ...
... a_n = 2·(-3)^(n-1)
45 45 90 triangle
a = 9√2 / √2
a = 9
answer
a = 9
