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3 years ago

Please help me ASAP easy problem giving brainlist!!

Mathematics

1 answer:

a_sh-v [17]3 years ago

8 0

Answer:

A and C

Step-by-step explanation:

you will see a double sign inequality when your circle on the number line is shaded in. aka a closed circle

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It take 10 road workers 5 days to complete a road repair when working 2 hours a day.Working at the same Pace, how many days will

ludmilkaskok [199]

Answer:

The workers will need 10 days to finish the job.

Step-by-step explanation:

To solve this question we can use a compound rule of three. We have:

10 road workers -> 5 days -> 2h/day

2 road workers -> x days -> 5h/days

The first thing we should do is analyze how the proportions between the variables work, if they're inversely or directly proportional. If we raise the number of workers we expect that the amount of days needed to finish the job lowers and if we raise the number of hours worked in a day we expect that the workers would need less days to finish the job. So we need to invert the fractions that are inversely proportional to the amount of days worked, then we have:

2 -> 5 -> 5

10-> x -> 2

x = (5*2*10)/(2*5) = 100/10 = 10 days

8 0

3 years ago

Help ASAP !!!!!!!!!!!!!!!

Brrunno [24]

1 1/2 + 1 1/3 is 2 5/6

7 0

3 years ago

Read 2 more answers

Which expression could represent the length of a rectangle that has an area equal to 4x2+12x?

grandymaker [24]

there are two expressions that can represent the length of the rectangle, these two expressions are:

L = x

L = (4x + 12)

<h3>Which expression could represent the length of the rectangle?</h3>

Remember that for a rectangle of length L and width W, the area is given by:

A = L*W

In this case, we know that the area is:

$A = 4x^2 + 12x$

We can factorize that expression into:

$A = x*(4x + 12)$

So there are two expressions that can represent the length of the rectangle, these two expressions are:

L = x

L = (4x + 12)

If you want to learn more about rectangles:

brainly.com/question/17297081

#SPJ1

6 0

1 year ago

A drum has a diameter of 10 inches. find the area of the top of the drum. use 3.14 for pi.

icang [17]

Answer:

My answer is 78.55

Step-by-step explanation:

I've given the steps. Hope it really helps

4 0

3 years ago

Read 2 more answers

A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa

gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4 | red dice) = $\dfrac{1}{6}$

P (4 | green dice) = $\dfrac{3}{6}$ = $\dfrac{1}{2}$

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = $\dfrac{1}{2}$

The probability of two 1's and two 4's in the first dice can be calculated as:

= $\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^4$

= $\dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4$

= $\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4$

= $6 \times ( \dfrac{1}{6})^4$

= $(\dfrac{1}{6})^3$

= $\dfrac{1}{216}$

The probability of two 1's and two 4's in the second dice can be calculated as:

= $\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^2 \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2$

= $\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2$

= $6 \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2$

= $( \dfrac{1}{6}) \times ( \dfrac{3}{6})^2$

= $\dfrac{9}{216}$

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = $\dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}$

The probability of two 1's and two 4's in both die = $\dfrac{1}{432} + \dfrac{1}{48}$

The probability of two 1's and two 4's in both die = $\dfrac{5}{216}$

By applying Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's ) = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's ) = $\dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}$

P(second die (green) | two 1's and two 4's ) = $\dfrac{0.5 \times 0.04166666667}{0.02314814815}$

P(second die (green) | two 1's and two 4's ) = 0.9

Thus; the probability the die chosen was green is 0.9

8 0

3 years ago