Answer:
12
Step-by-step explanation:
For the top triangle, he has 3 options
3C1 = 3
For the middle one, he can't use the top triangle's colour, so 2 options
2C1 = 2
For the ones on sides of the middle one, 2 options each
2C1 × 2C1 = 4
3 × 2 × 2 × 2 = 24
These include all three outer ones same, so subtract 3
Also, these include 2 of the three outer ones same, so subtract:
3C2 × 3 = 9
24 - 3 - 9 = 12
Number of friends - x
50-3x=2
-3x=-48
3x=48
x=16
Jack has 16 friends.
As given Chole and Tinos age , the present age of Tino is equal to 15 years.
As given,
Let x and y be the present age of Chole and Tino. respectively.
Combined age = 48
Given condition,
x + y = 48 _______(1)
Three years ago
x - 3 = 2y
⇒x =2y +3 _______(2)
Substitute the value of x in (1),
2y+3 +y =48
⇒ 3y = 45
⇒ y = 15years
Therefore , as given Chole and Tinos age , the present age of Tino is equal to 15 years.
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Answer:
Height of second tower = 17.32m
Step-by-step explanation:
I have attached a diagram depicting the question.
From the diagram, The first tower is depicted by side AEB and the second tower CD.
While d is the distance that separates the two towers and it's given as 15m.
Now, since the angle of depression of the second tower’s base is 60°, then for triangle BAC. Angle C = 60°.
Thus; using trigonometric ratios;
tan 60° = AB/AC.
This gives; AB = d*tan 60°
Similarly, for the triangle BED, BE = d*tan 30°
Since, AE = CD, thus ;
CD = AB − BE
CD = d (tan 60° − tan 30°)
CD = 15(1.7321 − 0.5774)
CD = 15 × 1.1547
CD ≈ 17.32 m.
So, height of second tower = 17.32 m