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AfilCa [17]
3 years ago
7

Molly walks to Raven's house, which is 3 miles due east of her house. Then she and Raven walk to the library, which is 4 miles d

ue north of Raven's house. Molly then walks home. If she averages walking 3 miles per hour, how long does Molly spend walking?
Mathematics
2 answers:
Rudiy273 years ago
8 0

Answer:

3 hours and twenty five minutes, i think

Step-by-step explanation:


Sliva [168]3 years ago
3 0

Answer:

4 hours

Step-by-step explanation:

First we find the distance between the library and Molly's house.

The line segment from Molly's house to Raven's house, 3 miles, and the line segment from Raven's house to the library, 4 miles, form the legs of a right triangle.  Using the Pythagorean theorem,

a²+b²=c²,

3²+4²=c²

9+16=c²

25=c²

Take the square root of each side:

√(25) = √(c²)

5 = c

This makes the total number of miles Molly walks

3+4+5 = 12 miles.

Since she travels 3 miles per hour, she travels 12/3 = 4 hours.

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Step-by-step explanation: sorry lol

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Read 2 more answers
A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
2 years ago
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