Let “x” be the cost of an adult ticket let “y” be the cost of a child ticket 1st day: 50=6x+8y 2nd day: 53=7x+8y Let both equations equal 0 0=6x+8y-50 0=7x+8y-53 Let equation 1 =equation 2 6x+8y-50=7x+8y-53 Isolate x 7x-6x=53-50+8y-8y x=3 substitute x=3 into equation 1 6(3)+8y=50 y=4 Therefore the cost of a child ticket is $3 and the cost of an adult ticket is $4
