Answer:
Area =25+6 =31m^2
Perimeter =30m^2 or 29.72m^2 to 2dp.
Step-by-step explanation:
We can show perimeter to match the 1/3 less rule in 10% values when the shape cuts into the square by 1/10th in total. = 10/100 -1/3
Area of Whole shape = 35 cm (as we 7x5) -1/3 of 1 x 4 = 033 x 4 =1.32 = 33.78sq^2
But minus 1/3 of 1 = 0.33 so we multiply this by 4 sides = 4 x 0.33 = 1.32 which still rounds as 1 and we find area
But because there are 2 changes on each shape we need to refresh 1.32 x 4 again = 5.28 = 29.72
So that area of 35 -5.28 = 29.72. =30m^2
Area of shaded region =Area of square- [Area of rect 1 + Area of rect 2+3] Percentage = 5x 5 = 25 (r2+3 = 3x 1 x2) = 6
Area =25+6 =31m^2
Area Prove = un-shaded = 1 x 0.75 x 4 = 3
31/3 = 10 1/3 % un-shaded = 10.33% un-shaded.
Which proves the 10 2/3 value has been proved through a higher 10.66 perimeter value 10.66p = 10% -2/3
This represents the 2/3 curve
It also represents the way perimeter can represent area in ratio for un-shaded to shaded areas. In this case it was 1 1/3 : 10
This is because if we wanted to add the total areas we would have 31m^2 +3m^2 which makes 34m^2
if we didn't round up initially then we would have had 30.72.+ 3 = 33.72m^2 for the entire shape area = 34m^2 shaded and un-shaded.
So in theory show 30.72m^2= Area for inner section shaped like a plus sign.
3m^2 = Area for unshaded squares combined
3 ÷ 4 = 0.75m^2= Area for each un-shaded corner.
added together = 3 + 30.78 = 33.78 = 34m^2 as once found.
