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daser333 [38]
3 years ago
15

Triangle ABC is congruent to triangle XYZ. Angle A measures 50 angle B measures (2x + 40) and angle Y measures (4x+8) Find the v

alue of x.
Mathematics
1 answer:
pickupchik [31]3 years ago
6 0
Angle B = Angle Y
2x + 40 = 4x + 8
40 = 2x + 8
32 = 2x
16 = x
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Can someone help me please.
Novosadov [1.4K]

Answer:

1 is  6.45

Step-by-step explanation:

3.25+1.55+1.65=6.45

6 0
2 years ago
Choose the constant term that completes the perfect square trinomial.<br><br> y2 + y
Oduvanchick [21]

Hello!

First off, please write y2 + y as y^2 + y. The " ^ " symbol denotes exponentiation, whereas y2 is meaningless.

To find the constant term in question, take half of the coefficient of y (that is, take 1/2) and square it. Then we have y2 + y + 1/4.

The constant term in question is 1/4.


3 0
3 years ago
PLZ HELP WILL GIVE BRAINLEST
Svetradugi [14.3K]

Answer:

The first one (Cedric is correct because he used the inverse of subtraction and added 4.5)

Step-by-step explanation:

First....I'll do it my way

z - 4.5 = -1.5

Add 4.5 on both sides

z - 4.5 + 4.5 = -1.5 + 4.5

z = 3

This should be our answer.....and so who did it right?

Cedric did

Which is the true statement?

Cedric is correct because he used the inverse of subtraction and added 4.5

Hope this helped!

Have a supercalifragilisticexpialidocious day!

8 0
3 years ago
The focus of a parabola is (-3,-5) The directrix of the parabola is y=2
cricket20 [7]

Check the picture below.

so the focus point is there, and the directrix is above it, meaning is a vertical parabola and is opening downwards, since the parabola opens up towards the focus.

now, the vertex is half-way between those two guys, at a "p" distance from either one, if we move over the y-axis from -5 to +2, we have 7 units, half-way is 3.5 units, and that puts us at -1.5 or -1½, as you see in the picture, so the vertex is then at (-3 , -1½).

so the distance from the vertex to the focus point  is then 3½ units, however since the parabola is opening downwards, "p" is negative, thus "p = 3½".

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{using this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \begin{cases} h=-3\\ k=-\frac{3}{2}\\[0.7em] p=-\frac{7}{2} \end{cases}\implies 4\left( -\cfrac{7}{2} \right)\left[ y-\left(-\cfrac{3}{2} \right) \right]=\left[ x-\left( -3 \right) \right]^2 \\\\\\ -14\left( y+\cfrac{3}{2} \right)=(x+3)^2\implies y+\cfrac{3}{2} =-\cfrac{(x+3)^2}{14} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{14}(x+3)^2-\cfrac{3}{2}~\hfill

4 0
3 years ago
Plz help I really need this for my paper
Verdich [7]
Go to mathology.com it helps me when i really need it


4 0
4 years ago
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