Answer:
1 is 6.45
Step-by-step explanation:
3.25+1.55+1.65=6.45
Hello!
First off, please write y2 + y as y^2 + y. The " ^ " symbol denotes exponentiation, whereas y2 is meaningless.
To find the constant term in question, take half of the coefficient of y (that is, take 1/2) and square it. Then we have y2 + y + 1/4.
The constant term in question is 1/4.
Answer:
The first one (Cedric is correct because he used the inverse of subtraction and added 4.5)
Step-by-step explanation:
First....I'll do it my way
z - 4.5 = -1.5
Add 4.5 on both sides
z - 4.5 + 4.5 = -1.5 + 4.5
z = 3
This should be our answer.....and so who did it right?
Cedric did
Which is the true statement?
Cedric is correct because he used the inverse of subtraction and added 4.5
Hope this helped!
Have a supercalifragilisticexpialidocious day!
Check the picture below.
so the focus point is there, and the directrix is above it, meaning is a vertical parabola and is opening downwards, since the parabola opens up towards the focus.
now, the vertex is half-way between those two guys, at a "p" distance from either one, if we move over the y-axis from -5 to +2, we have 7 units, half-way is 3.5 units, and that puts us at -1.5 or -1½, as you see in the picture, so the vertex is then at (-3 , -1½).
so the distance from the vertex to the focus point is then 3½ units, however since the parabola is opening downwards, "p" is negative, thus "p = 3½".
![\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{using this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bparabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%204p%28x-%20h%29%3D%28y-%20k%29%5E2%20%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Busing%20this%20one%7D%7D%7B4p%28y-%20k%29%3D%28x-%20h%29%5E2%7D%20%5Cend%7Barray%7D%20%5Cqquad%20%5Cbegin%7Barray%7D%7Bllll%7D%20vertex%5C%20%28%20h%2C%20k%29%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf \begin{cases} h=-3\\ k=-\frac{3}{2}\\[0.7em] p=-\frac{7}{2} \end{cases}\implies 4\left( -\cfrac{7}{2} \right)\left[ y-\left(-\cfrac{3}{2} \right) \right]=\left[ x-\left( -3 \right) \right]^2 \\\\\\ -14\left( y+\cfrac{3}{2} \right)=(x+3)^2\implies y+\cfrac{3}{2} =-\cfrac{(x+3)^2}{14} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{14}(x+3)^2-\cfrac{3}{2}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20h%3D-3%5C%5C%20k%3D-%5Cfrac%7B3%7D%7B2%7D%5C%5C%5B0.7em%5D%20p%3D-%5Cfrac%7B7%7D%7B2%7D%20%5Cend%7Bcases%7D%5Cimplies%204%5Cleft%28%20-%5Ccfrac%7B7%7D%7B2%7D%20%5Cright%29%5Cleft%5B%20y-%5Cleft%28-%5Ccfrac%7B3%7D%7B2%7D%20%5Cright%29%20%5Cright%5D%3D%5Cleft%5B%20x-%5Cleft%28%20-3%20%5Cright%29%20%5Cright%5D%5E2%20%5C%5C%5C%5C%5C%5C%20-14%5Cleft%28%20y%2B%5Ccfrac%7B3%7D%7B2%7D%20%5Cright%29%3D%28x%2B3%29%5E2%5Cimplies%20y%2B%5Ccfrac%7B3%7D%7B2%7D%20%3D-%5Ccfrac%7B%28x%2B3%29%5E2%7D%7B14%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20y%3D-%5Ccfrac%7B1%7D%7B14%7D%28x%2B3%29%5E2-%5Ccfrac%7B3%7D%7B2%7D~%5Chfill)
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