Find the measure of the indicated angle to the nearest degree.

What is the answer for this i need help!!??

Answer:

-243

Step-by-step explanation:

${( - 3)}^{ - 5} = \frac{1}{x} \\ \\ \therefore \: \frac{1}{ {( - 3)}^{ 5} } = \frac{1}{x} \\ \\ \therefore \: {( - 3)}^{ 5} = x \\ \\ \therefore \: - 243 = x \\ \\ \huge \red{ \boxed{\therefore \: x = - 243}}$

5 0

4 years ago

Help, 100 pts + brainlist for first person to answer

Blababa [14]

Answer:

About 4.

Step-by-step explanation:

It is actaully 3.95 but if you were rounding and in fraction form, it would be four! Hope this helps!

8 0

2 years ago

Read 2 more answers

Graph the equation y=-(x+2)^2+7

ELEN [110]

Step-by-step explanation:

Distribute:

=−x2+−4x+−4+7

Combine Like Terms:

=−x2+−4x+−4+7

=(−x2)+(−4x)+(−4+7)

=−x2+−4x+3

Answer:

=−x2−4x+3

7 0

3 years ago

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

3 years ago

H. Four businessman invested a sum of Rs.

balandron [24]

Answer:

The answers are in solutions.

Step-by-step explanation: