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andre [41]
2 years ago
14

50 points,

Mathematics
1 answer:
weeeeeb [17]2 years ago
4 0

Answer:

Sum of the areas of the three circles is 91.06 units².

Step-by-step explanation:

Given:

Let the  radius of the circle with center D  = x

Let the radius  of the circle with center E  = y  

Let the radius  of the circle with center F  = z

To Find:

Sum of the areas of the three circles = ?

Solution:

So we have these equations

DE =x + y = 5............( 1 )\\EF = x + z = 6..........( 2 )\\DF =y + z = 7...........( 3 )

Subtract the second equation from the  first  and we have that

y- z=-1

Add this to equation to the third equation  and we have that

\therefore 2y= 6\\\\\therefore y= 3\\\\\therefore x = 2\\\\\therefore z = 4

Now we have Area of Circle

\textrm{Area of Circle}=\pi (Radius)^{2}

Substituting Radius we get

\textrm{Area of Circle with center D}=3.14\times 2^{2}=12.56\ units^{2}

\textrm{Area of Circle with center E}=3.14\times 3^{2}=28.26\ units^{2}

\textrm{Area of Circle with center F}=3.14\times 4^{2}=50.24\ units^{2}

∴ \textrm{Sum of the areas of the three circles}=12.56+28.26+50.24=91.06\ units^{2}

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See attachment for cube

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