Question

Pls help me for question no.4

Answer 1

Answer:

Area of the composite figure = 75.25 cm²

Step-by-step explanation:

Question (4). Given figure is a composite figure having,

(1). Right triangle STU

(2). A kite PSUV

(3). A trapezoid PQRS

Now we will calculate the area of each figure.

(1). Area of the right triangle = $\frac{1}{2}(\text{ST})(\text{TU})$

                                              = $\frac{1}{2}(3.5)(3)$

                                              = 5.25 cm²

(2). Area of the kite PSUV = $\frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})$

                                           = $\frac{1}{2}(\text{PU})(\text{SV})$

                                           = $\frac{1}{2}(\text{TS+RQ})(\text{SV})$

                                           = $\frac{1}{2}(3.5+7)(6)$ [Since SV = 2 × 3 = 6 cm]

                                           = $3\times 10.5$

                                           = 31.5 cm²

(3). Area of the trapezium = $\frac{1}{2}(b_1+b_2)(h)$ [Where $b_1$ and $b_2$ are the bases and h is the distance between the bases]

                                           = $\frac{1}{2}[(7-3)+7](7)$

                                           = $\frac{77}{2}$

                                           = 38.5 cm²

Total area of the given figure = 5.25 + 31.5 + 38.5

                                                 = 75.25 cm²