Answer:
Step-by-step explanation:
In the figure attached,
Vertices of the triangle ABC are A(-4, 4), B(-1, 4) and (-1, 2)
When we reflect this figure across a line y = 1
Vertices of the image triangle A'B'C' will be
Coordinates of A'
A(-4, 4) → A'[(1 + 5), 4]
→ A'(6, 4)
Coordinates of B'
B(-1, 4) → B'(-1 + 4, 4)
→ B'(3, 4)
Coordinates of C',
C(-1, 2) → C'[(-1 + 4), 2]
→ C'(3, 2)
Graph these points and join them to form the image triangle A'B'C'.
Answer:
a) The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.
b) The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.
c) The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).
d) The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of .
Standard error:
The standard error is:
Margin of error:
The margin of error is:
The confidence interval is:
Sample proportion plus/minus margin of error. So
In a simple random sample of 1500 young Americans 1305 had earned a high school diploma.
This means that
a. What is the standard error for this estimate of the percentage of all young Americans who earned a high school diploma?
0.0087*100% = 0.87%.
The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.
b. Find the margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma.
95% confidence level
So , z is the value of Z that has a p-value of
, so
.
Then
0.0171*100% = 1.71%
The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.
c. Report the 95% confidence interval for the percentage of all young Americans who earned a high school diploma.
87% - 1.71% = 85.29%
87% + 1.71% = 88.71%.
The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).
d. Suppose that in the past, 80% of all young Americans earned high school diplomas. Does the confidence interval you found in part c support or refute the claim that the percentage of young Americans who cam high school diplomas has increased? Explain.
The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.
