Answer:division property of equality
Step-by-step explanation: Because 0.36x divided by 0.36 is 1x. -1.8 divided by 0.36 is -5. Couuld you give me brainleist
Answer: Area = 6m²
Smaller number = 16
Hours = 9.6 h
Step-by-step explanation:
A rectangle is 5 meters longer than its width. If the length is shortened by 2 meters and width is increased by 1 meter, the area remains the same. Find the area of the rectangle.
1) w = x m 2) w = x + 1 m
l = x + 5 m l = x + 5 - 2 = x + 3 m
A₁ = A₂
A = w*l
A₁ = x(x+5) = x² + 5x
A₂ = (x+1)(x+2) = x² + x + 2x + 2 = x² + 3x + 2
A₁ = A₂
x² + 5x = x² + 3x + 2
5x - 3x = 2
2x = 2
x = 1
A₁ = x(x+5) = 1.6 = 6 m²
The ratio of two numbers is 2:5. If the larger number is 40, what is the smaller number.
<u> 2 </u> = <u> x </u>
5 40
5x = 80
x = 80/5 = 16
Sixteen construction workers can finish cementing a floor of a building in 3 hours. On a certain day, only 5 construction workers are available for the job. How long will it take the 5 construction workers to do the cementing job?
workers hours
16 3
5 x
↑ ↓ inversely proportional
<u> 5 </u> = <u> 3 </u>
16 x
5x = 16*3
5x = 48
x = 48/5
x = 9.6 h
Answer:
Step-by-step explanation:
125x^9 = (5x^3)^3
64y^12 = (4y^4)^3
If you want that factored it is
(5x^3 + 4y^4)( (5x^3)^2 - 5x^3*4y^4 + (4y^4)^2 )
(5x^3 + 4y^4)( 25x^6 - 20x^3y^4 + 16y^8)
Answer: 28x+42y=3
Step-by-step explanation:
Given: The point (x,y) is equidistant from the points
.
By distance formula the distance between
is
![D_1=\sqrt{(x-\frac{-1}{4})^2+(y-(-4))^2} \\=\sqrt{(x+\frac{1}{4})^2+(y+4)^2}](https://tex.z-dn.net/?f=D_1%3D%5Csqrt%7B%28x-%5Cfrac%7B-1%7D%7B4%7D%29%5E2%2B%28y-%28-4%29%29%5E2%7D%20%5C%5C%3D%5Csqrt%7B%28x%2B%5Cfrac%7B1%7D%7B4%7D%29%5E2%2B%28y%2B4%29%5E2%7D)
Similarly, the distance between
is
![D_2=\sqrt{(x-\frac{13}{4})^2+(y-(\frac{5}{4}))} \\=\sqrt{(x-\frac{13 }{4})^2+(y-\frac{5}{4})^2}](https://tex.z-dn.net/?f=D_2%3D%5Csqrt%7B%28x-%5Cfrac%7B13%7D%7B4%7D%29%5E2%2B%28y-%28%5Cfrac%7B5%7D%7B4%7D%29%29%7D%20%5C%5C%3D%5Csqrt%7B%28x-%5Cfrac%7B13%20%7D%7B4%7D%29%5E2%2B%28y-%5Cfrac%7B5%7D%7B4%7D%29%5E2%7D)
Since,
![D_1=D_2\\\\\Rightarrow\ \sqrt{(x+\frac{1}{4})^2+(y+4)^2}=\sqrt{(x-\frac{13}{4})^2+(y-\frac{5}{4})^2}\\\\\text{Squaring on the sides, we get}\\\Rightarrow(x+\frac{1}{4})^2+(y+4)^2=(x-\frac{13}{4})^2+(y-\frac{5}{4})^2\\\\\Rightarrow[x^2+\frac{1}{2}x+\frac{1}{16}]+y^2+8y+16=x^2-\frac{13}{2}x+\frac{169}{16}+y^2+\frac{25}{4}-\frac{5}{2}y\\\\\Rightarrow7x+\frac{21}{2}y=\frac{3}{4}\\\Rightarrow28x+42y=3](https://tex.z-dn.net/?f=D_1%3DD_2%5C%5C%5C%5C%5CRightarrow%5C%20%5Csqrt%7B%28x%2B%5Cfrac%7B1%7D%7B4%7D%29%5E2%2B%28y%2B4%29%5E2%7D%3D%5Csqrt%7B%28x-%5Cfrac%7B13%7D%7B4%7D%29%5E2%2B%28y-%5Cfrac%7B5%7D%7B4%7D%29%5E2%7D%5C%5C%5C%5C%5Ctext%7BSquaring%20on%20the%20sides%2C%20we%20get%7D%5C%5C%5CRightarrow%28x%2B%5Cfrac%7B1%7D%7B4%7D%29%5E2%2B%28y%2B4%29%5E2%3D%28x-%5Cfrac%7B13%7D%7B4%7D%29%5E2%2B%28y-%5Cfrac%7B5%7D%7B4%7D%29%5E2%5C%5C%5C%5C%5CRightarrow%5Bx%5E2%2B%5Cfrac%7B1%7D%7B2%7Dx%2B%5Cfrac%7B1%7D%7B16%7D%5D%2By%5E2%2B8y%2B16%3Dx%5E2-%5Cfrac%7B13%7D%7B2%7Dx%2B%5Cfrac%7B169%7D%7B16%7D%2By%5E2%2B%5Cfrac%7B25%7D%7B4%7D-%5Cfrac%7B5%7D%7B2%7Dy%5C%5C%5C%5C%5CRightarrow7x%2B%5Cfrac%7B21%7D%7B2%7Dy%3D%5Cfrac%7B3%7D%7B4%7D%5C%5C%5CRightarrow28x%2B42y%3D3)