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4 years ago

13

MNOP is a trapezoid with median QR find X

2 answers:

NemiM [27]4 years ago

6 0

Answer:

B

Step-by-step explanation:

Since QR is the median and it is 12. and NO is 8. 12-8=4.

So I'm going to say 2x+6 will equal 16.

2x+6=16

2x=10

x=5

Ilya [14]4 years ago

6 0

Answer:

B. x = 5

Step-by-step explanation:

Trapezoid are quadrilateral because they have 4 sides. From the trapezoid above, the side NO is parallel to side MP and are known as the base.

The median QR is parallel to each base(NO and MP). The length of the median QR equals one half the sum of the two parallel bases. Mathematically, this can be represented as

Length of median(QR) = 1/2 × (NO + MP)

12 = 1/2 × (8 + 2x + 6)

12 = 1/2 ×(14 + 2x)

cross multiplying

12 × 2 = 14 + 2x

24 = 14 + 2x

24 - 14 = 2x

10 = 2x

x = 10/2

x = 5

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3 years ago

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3 years ago

Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

5 0

3 years ago

HELP PLEASE!!! ive been stuck on this for a week and i need to turn it in.

Aleksandr-060686 [28]

R= 98600/30 $/day

R= 9860/3

Debt= 1200000-98600

=1101400

Debt= R•days

1101400=9860/3•(days)

335.1= days

336 days because you can't have a partial day and 335 days would leave $367 of debt still.

It would take the company 336 more days to earn back it's investment.

8 0

3 years ago